Answer:
Cl
Explanation:
⁴¹Ca has an atomic number equal to 20, it means that it has 20 protons and 20 electrons ad its neutral state. In the decay by electron capture, it will lose one electron and will become a cation, but the mass (41) and the atomic number will remain the same.
When Ca⁺ undergoes alpha decay, it will lose an alpha particle, which has mass 4 and 2 protons.
⁴¹₂₀Ca⁺ → ³⁷₁₈X⁺ + ⁴₂α
To be stable, X will lose a proton and will become ³⁷₁₇X. The element which has atomic number 17 is chlorine, Cl.
I think the correct answer would be none, because the wall will block the radiation. Alpha particles can only penetrate a very thin sheet of paper and is totally blocked by the concrete. As these particles move through the air, it loses energy from the collisions with air molecules making it less penetrating.<span />
Explanation:
It is known that for first order reaction, the equation is as follows.
t = ![\frac{2.303}{K} log \frac{[C_{4}H_{8}]_{o}}{[C_{4}H_{8}]_{t}}](https://tex.z-dn.net/?f=%5Cfrac%7B2.303%7D%7BK%7D%20log%20%5Cfrac%7B%5BC_%7B4%7DH_%7B8%7D%5D_%7Bo%7D%7D%7B%5BC_%7B4%7DH_%7B8%7D%5D_%7Bt%7D%7D)
t = ?, K = rate constant = 79 1/s
Initial conc. of
= 1.68
Decompose amount of
= 52% of 1.68
= 
= 0.8736
= 0.87
Now,
= (1.68 - 0.87)
= 0.81
Therefore, calculate the value of t as follows.
t = ![\frac{2.303}{K} log \frac{[C_{4}H_{8}]_{o}}{[C_{4}H_{8}]_{t}}](https://tex.z-dn.net/?f=%5Cfrac%7B2.303%7D%7BK%7D%20log%20%5Cfrac%7B%5BC_%7B4%7DH_%7B8%7D%5D_%7Bo%7D%7D%7B%5BC_%7B4%7DH_%7B8%7D%5D_%7Bt%7D%7D)
= 
= 
=
s
= 
Thus, we can conclude that 0.00921 s will be taken for 52% of the cyclobutane to decompose.