Answer:
It is mostly water (up to 95% by volume), and contains dissolved proteins (6–8%) (e.g. serum albumins, globulins, and fibrinogen), glucose, clotting factors, electrolytes (Na+, Ca2+, Mg2+, HCO3−, Cl−, etc.), hormones, carbon dioxide (plasma being the main medium for excretory product transportation) and oxygen.
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moles NaOH = c · V = 0.2753 mmol/mL · 43.44 mL = 11.959032 mmol
moles H2SO4 = 11.959032 mmol NaOH · 1 mmol H2SO4 / 2 mmol NaOH = 5.979516 mmol
Hence
[H2SO4]= n/V = 5.979516 mmol / 54.69 mL = 0.1093 M
The answer to this question is [H2SO4] = 0.1093 M
Answer:
Q = -3980.9 j
Explanation:
Given data:
Mass of sample = 30 g
Initial temperature = 56.7 °C
Final temperature = 25 °C
Specific heat of water = 4.186 j/g.°C
Amount of heat released = ?
Formula:
Q = m.c.ΔT
Q = heat released
m = mass of sample
c = specific heat of given sample
ΔT = change in temperature
Solution:
ΔT = T2 -T1
ΔT = 25 °C - 56.7 °C = - 31.7°C
Q = m.c.ΔT
Q = 30 g × 4.186 j/g.°C × - 31.7°C
Q = -3980.9 j
2HNO3 + Ca(OH)2 ==> Ca(NO3)2 + 2H2O
<span>mols Ca(OH)2 = M x L = ? </span>
<span>Using the coefficients in the balanced equation, convert mols Ca(OH)2 to mols HNO3. </span>
<span>Then M HNO3 = mols HNO3/LHNO3. You have mols and M, solve for L.</span>
Equation balance:
2Al(OH)3 + 3H2SO4 → Al2(SO4)3 + 6H2O
2Al(OH)3+3H2SO4
H=12
SO4=3
O=6
Al=2
Al2(SO4)3+6H2O
H=12
SO4=3
O=6
Al=2
