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viva [34]
3 years ago
13

Strong acids are those that ionizes almost completely in water. to be considered a strong acid, an acid must have an acid ioniza

tion constant ka > 55. the strong acid hcl in aqueous solution undergoes the ionization reaction: hcl(aq) + h2o(l) ⇋ h3o+(aq) + cl-(aq) and its ka = 2.00 x 106. if the concentrations of h3o+ and cl- are both found to be equal to 0.153 mol/l what is the remaining concentration hcl that is not ionized
Chemistry
1 answer:
quester [9]3 years ago
8 0
Ka  is  the  equilibrium  constant  for  the  ionization for a reaction. It  is  calculated  as  follows
ka  is equal  to (H3o ions)(A-) divided by (HA)
  2.00x106i s  equal  to 0.153x0.153 divided by ( HA)
  (2.00x106)HA is  equal  to  0.023409
  HA concentration  is  therefore equal to 0.023409/2.00x106 which  is 1.104x10^-4moles/litre

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Which of the following is true for balancing equations?
algol [13]

Answer:

A.

Explanation:

An equation with the equal amount and proportion of atoms of each element on both sides of the reaction is commonly referred to as a balanced chemical equation.

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under certain water​ conditions, the free chlorine​ (hypochlorous acid,​ hocl) in a swimming pool decomposes according to the la
ivolga24 [154]

Answer:

1.7 ppm

Explanation:

Original amount N' = 2.6 ppm

time to testing t = 24 hr

final amount N = 2.1 ppm

Using exponential inhibited decay, we have

N = N'e^(-kt)

Where

N is the new reading

N' is the original reading

t is the decay time

k is the decay constant

Substituting, we have

2.1 = 2.6 x e^(-k x 24)

2.1 = 2.6 x e^(-24k)

0.808 = e^(-24k)

We take the natural log of both sides of the equation

Ln 0.808 = Ln (e^(-24k))

-0.213 = - 24k

K = 0.213/24 = 0.00886

After 48 hrs, the reading of free chlorine will be

N = 2.6 x e^(-0.00886 x 48)

N = 2.6 x e^(-0.425)

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5 0
3 years ago
Do ionic or covalent substances tend to produce more ions in solution? ...?
sasho [114]
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8 0
4 years ago
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Balance the equations by inserting coefficients as needed.
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Answer:

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Explanation:

7 0
4 years ago
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What is the weight of a 90kg man standing on the moon, where gmoon = 1.64 m/s2?
Doss [256]

Answer:

The weigth of a 90kg man standing on the moon is <u><em>147.6 N (option C)</em></u>

Explanation:

Weight is called the action exerted by the force of gravity on the body.

The mass (amount of matter that a body contains) of an object will always be the same, regardless of where it is located. Instead, the weight of the object will vary according to the force of gravity acting on it.

The formula that allows you to calculate the weight of any body is:

W = m*g

where:

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In this case,  the mass m has a value of 90 kg and the gravity g has a value of 1.64 m/s², which is the value of the acceleration of gravity of the moon. Then:

W=90 kg* 1.64 m/s²

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Finally, <u><em>the weigth of a 90kg man standing on the moon is 147.6 N (option C)</em></u>

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4 years ago
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