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3 years ago

5. The benzoate anion is the conjugate base of the benzoic acid. Potassium

Chemistry

2 answers:

Liono4ka [1.6K]3 years ago

5 0

Answer: c weak acid

Explanation:

The faster the rate of leaving proton, the more strong the acid is. Due to the resonance structure of benzoic acid, power of leaving proton is restricted

rosijanka [135]3 years ago

3 0

Answer: The benzoic acid is a weak acid.

Explanation:

According to the Bronsted-Lowry conjugate acid-base theory:

An acid is defined as a substance which looses donates protons and thus forming conjugate base.
A base is defined as a substance which accepts protons and thus forming conjugate acid.

The chemical equation for the reaction of potassium benzoate with water follows:

$C_6H_5COOK+H_2O\rightarrow C_6H_5COOH+KOH$

Here, benzoate anion is accepting a proton from water and is acting as conjugate base. Water is acting as conjugate acid.

The solution formed is basic solution because of the formation of potassium hydroxide.

When a strong base and weak acid reacts, it leads to the formation of basic solution.

Hence, the benzoic acid is a weak acid.

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trapecia [35]

Answer:

The molecule has two chiral carbons

Explanation:

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3 years ago

Determine the final temperature of a system, if 120 grams had an initial temperature of 80°C and mixes with 3,000 g of water at

frutty [35]

Answer:

The final temperature of the mixture is 22.3°C

Explanation:

Assuming that the 120 g substance at 80°C is water, final temperature of the mixture can be determined using the formula:

Heat lost = Heat gained

Heat = mc∆T where m is mass, c is specific heat capacity of water, and ∆T is the temperature change = Tfinal - Tinitial.

Let the final temperature be T

Heat lost = 120 × c × (T - 80)

Heat gained = 3000 × c × ( T - 20)

Equating the heat lost and heat gained

120 × c × -(T - 80) = 3000 × c × (T - 20)

9600 - 120T = 3000T - 60000

60000 + 9600 = 3000T + 120T

69600 = 3120T

T = 69600/3120

T = 22.3°C

Therefore, the final temperature of the mixture is 22.3°C

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3 years ago

Zn + 2 HCl → ZnCl2 + H2

MrRissso [65]

Answer:

10.1g of H₂ are produced

Explanation:

To solve this question we need, first, to convert the mass of each reactant to moles and, using the chemical reaction, find limiting reactant. With limiting reactant we can find the moles of H2 and its mass:

Moles Zn -Molar mass: 65.38g/mol-:

307g * (1mol / 65.38g) = 4.696 moles

Moles HCl -Molar mass: 36.46g/mol-:

381g HCl * (1mol / 36.46g) = 10.45 moles

For a complete reaction of 10.45 moles of HCl are required:

10.45 moles HCl * (1mol Zn / 2mol HCl) = 5.22 moles Zn

As there are 4.696 moles of Zn, Zn is the limiting reactant

The moles of H₂ produced = Moles of Zn added = 4.696 moles. The mass is-Molar mass H₂ = 2.16g/mol-:

4.696 moles * (2.16g / mol) =

<h3>10.1g of H₂ are produced</h3>

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Answer:

i.elements not obeying increasing atomic mass. ii.properties and uneven grouping.

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