How much kinetic energy does a system containing 5 moles of an ideal gas at 300.00 K possess? (decimal only)

Physics

1 answer:

maks197457 [2]3 years ago

8 0

Answer:

$K=18.70kJ$

Explanation:

The kinetic energy of an ideal gas is defined as:

$K=\frac{3}{2}nRT$

Here n is the number of moles of the gas, R is the ideal gas constant and T is the temperature of the gas. So, replacing the given values, we get the kinetic energy of the system:

$K=\frac{3(5mol)(8.31\frac{J}{mol\cdot K})(300K)}{2}\\K=18697.5J=18.70kJ$

You might be interested in

The molecules of a substance become more closely packed and move more quickly.

andrey2020 [161]

When the substance are moved close together and they move more quickly they get compressed.

4 0

3 years ago

A flashlight converts?

sammy [17]

Answer:

Energy conversion in flashlight.

Explanation:

When the switch of a flashlight is on, then the batteries inside them will be connected in a circuit and chemical energy from the batteries will be converted into electrical energy and then the electrical energy will be converted into light energy.

Light energy is also called electromagnetic energy.

Hence, among the given options the correct one is the first option that is:

1. Electrical energy into electromagnetic energy is the answer.

4 0

2 years ago

A geosynchronous Earth satellite is one that has an orbital period of precisely 1 day. Such orbits are useful for communication

koban [17]

Answer:

r = 4.24x10⁴ km.

Explanation:

To find the radius of such an orbit we need to use Kepler's third law:

$\frac{T_{1}^{2}}{T_{2}^{2}} = \frac{r_{1}^{3}}{r_{2}^{3}}$

<em>where T₁: is the orbital period of the geosynchronous Earth satellite = 1 d, T₂: is the orbital period of the moon = 0.07481 y, r₁: is the radius of such an orbit and r₂: is the orbital radius of the moon = 3.84x10⁵ km. </em>

From equation (1), r₁ is:

$r_{1} = r_{2} \sqrt[3] {(\frac{T_{1}}{T_{2}})^{2}}$