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Hitman42 [59]
3 years ago
11

Which material would you take, steel or bricks to design a bridge? Why?

Physics
2 answers:
Vesna [10]3 years ago
4 0

Answer:

steel

Explanation:

steel because steel has more power to hold something up, where bricks arent as stable

SVETLANKA909090 [29]3 years ago
4 0

Answer:Materials Used in Bridge Construction Stones, Timber, Concrete and Steel are the traditional materials that are used to carry out bridge construction. ... Brick was used as a subgroup construction material along with stone construction. Stones as ... This property of steel is an important criterion in the design of structures.

Explanation:

You might be interested in
Are There some sounds for which we are all deaf
lana66690 [7]

Answer: Infrasound is the span of low-frequency sounds below 20 Hz that fall below the hearing range of humans. While these sounds escape our ears, scientific instruments can detect them—and tell us some interesting things about the planet.

Explanation:

6 0
3 years ago
Determine the voltage ratings of the high-and-low voltage windings for this connection and the MVA rating of the autotransformer
SIZIF [17.4K]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

The High Voltage Rating for Auto - Transformer is 86kV

The  Low Voltage Rating for Auto - Transformer is 78kV

The MVA rating is 268.75MVA

b

The efficiency is 99.4%

Explanation:

From the question  we are given are given that

 The transformer has Mega Volt Amp rating of 25MVA

                          The frequency is 60-Hz

                           Voltage rating 8.0kV : 78kV

   The short circuit test gives : 453kV,321A,77.5kW

   The open circuit test gives : 8.0kV, 39.6A, 86.2kW

This can be represented on a diagram shown on the second uploaded image

From this diagram we can deduce that the The High Voltage Rating for Auto - Transformer is 86kV and the  Low Voltage Rating for Auto - Transformer is 78kV

 Now to obtain the current flowing through the 8kV  coil in the Auto-transformer we have

             \frac{25 \ Mega \ Volt\ Ampere }{8\ Kilo Volt}

The volt will cancel each other

             \frac{25*10^6}{8*10^3} =  3125\ A

 Now to obtain the required MVA rating we would multiply the value of Power obtained during the open circuit test by the value of the current calculated.we are making use of the power obtain during open circuit testing because the transformer at this point is not under any load.

MVA \ rating = (86*10^3)(3125) =268.75

We need to understand that Iron losses is due to open circuit test which has power = 86.2kW

While copper loss is due to short circuit test which has power = 77.5kW

The the current flowing through the secondary coil I_2 as shown in the circuit diagram can be obtained as

       I_2 = \frac{25*10^6}{78*10^3} =320.52 A \approx 321

Now the efficiency can be obtained as thus

           \frac{(operational \ MVA )*(Power factor \pf))}{(operational\  MVA (power factor pf) + copper loss + Iron loss)}*\frac{100}{1}

             =99.941%

8 0
3 years ago
Can a goalkeeper at his goal kick a soccer ball into the opponent’s goal without the ball touching the ground? The distance will
zmey [24]

The goalkeeper at his goal cannot kick a soccer ball into the opponent’s goal without the ball touching the ground

Explanation:

Consider the vertical motion of ball,

We have equation of motion v = u + at

     Initial velocity, u  = u sin θ

     Final velocity, v =  0 m/s    

     Acceleration = -g

     Substituting

                      v = u + at  

                      0 = u sin θ - g t

                      t=\frac{usin\theta }{g}

This is the time of flight.

Consider the horizontal motion of ball,

        Initial velocity, u =  u cos θ

        Acceleration, a =0 m/s²  

        Time, t=\frac{usin\theta }{g}  

     Substituting

                      s = ut + 0.5 at²

                      s=ucos\theta \times \frac{usin\theta }{g}+0.5\times 0\times (\frac{usin\theta }{g})^2\\\\s=\frac{u^2sin\theta cos\theta}{g}\\\\s=\frac{u^2sin2\theta}{2g}

This is the range.

In this problem

              u = 30 m/s

              g = 9.81 m/s²

              θ = 45° - For maximum range

Substituting

               s=\frac{30^2\times sin(2\times 45)}{2\times 9.81}=45.87m

Maximum horizontal distance traveled by ball without touching ground is 45.87 m, which is less than 95 m.

So the goalkeeper at his goal cannot kick a soccer ball into the opponent’s goal without the ball touching the ground

6 0
3 years ago
Density is found by dividing ____.
bezimeni [28]
<span>Mass represents the density of an object multiplied with the volume it occupies. As a result, an object's density is found by dividing its mass by its volume. So the answer is a.</span>
6 0
3 years ago
Read 2 more answers
2. A person applies a force of 66 N to a fridge as they push it across the length of a standard tennis court. So far today, the
Lubov Fominskaja [6]

Answer:

P=39.2205\, watt

E=374.948 \,cal

Explanation:

Given that:

  • force applied, F=66\,N
  • displacement, s=23.77\,m (length of a tennis court)
  • time taken for pushing, t = 40 s

Since, work is given by:

W=F.s

W=66\times 23.77

W=1568.82\,J

Now, power is given as:

P=\frac{W}{t}

P=\frac{1568.82}{40}

P=39.2205 \,watt

Calories consumed is:

E= 1568.82\times 0.239

E=374.948\, cal

3 0
3 years ago
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