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Greeley [361]
3 years ago
7

At standard temperature and pressure, carbon dioxide has a density of 1.98 kg/m3. What volume does 1.70 kg of carbon dioxide occ

upy at standard temperature and pressure?
Physics
1 answer:
nikitadnepr [17]3 years ago
8 0

Answer:

<h2>volume= 0.85m^3</h2>

Explanation:

<em>The density of a substance is defined as the mass per unit volume of the substance, the unit is in kg/m^3 and it is represented by the greek letter rho</em>

Step one:

given data

we are told that the density  of Co2=  1.98 kg/m3

and the mass of Co2 is= 1.70 kg

we know the relation between mass, volume and density is

density=mass/volume

make volume subject of formula we have

volume=mass/density

substitute we have

volume=1.7/1.98\\\\volume= 0.85m^3

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navik [9.2K]
I believe the answer is vehicle weight
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We humans are on track to increase the amount of CO2 in the atmosphere so that the concentration in the future more than double
Lapatulllka [165]

Answer:

Rapid increase in the temperature of the earth.

Explanation:

CO2 is known as a greenhouse gas. It is able to trap and retain infrared radiation in the earths atmosphere thereby causing a gradual rise in the temperature of the earth. If this doubled concentration of CO2 is sustained over a long period of time, it will eventually lead to melting of polar ice caps and consequent flooding. Gradually, the earth would be destroyed due to the scorching heat and attendant flood.

7 0
3 years ago
More people end up in U.S. emergency rooms because of fall-related injuries than from any other cause. At what speed v would som
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Answer:

v_{f}=6.47m/s

Explanation:

Given data

Distance d=7.00 ft= 7*(1/3.281) =2.1336m

Initial velocity vi=0m/s

To find

Final velocity

Solution

From Kinematic equation we know that:

v_{f}^{2} =v_{i}^{2}+2gd\\v_{f}^{2}=0+2(9.81m/s^{2} ) (2.1336m)\\v_{f}^{2}=41.86\\v_{f}=\sqrt{41.86}\\v_{f}=6.47m/s

6 0
3 years ago
A fire helicopter carries a 700-kg bucket of water at the end of a 20.0-m long cable. Flying back from a fire at a constant spee
rodikova [14]

Answer:

F = 50636.873 N

Explanation:

given,

bucket of water =  700-kg

length of cable = 20 m

Speed  = 40 m/s

angle of the cable = 38.0°

let air resistance be = F

tension in rope be = T

T cos 38° = m×g..................(1)

T sin 38^0= \dfrac{mv^2}{l} + F..........(2)

equation (1)/(2)

tan 38^0 =\dfrac{\dfrac{mv^2}{l} + F}{mg}

       0.781=\dfrac{\dfrac{700\times 40^2}{20} + F}{700\times 9.8}

           F = 50636.873 N

Hence the force exerted on the bucket is equal to F = 50636.873 N

5 0
3 years ago
13
gladu [14]

v = u + at

50 = 0 + a*10

50 = 10a

a = 5 m/s^2

4 0
2 years ago
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