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iogann1982 [59]
3 years ago
10

Eli rolled a ball down the cement sidewalk as hard as he could. The ball rolled for less than a minute before it came to a stop.

What force acted to slow and finally stop the ball? A. friction, acting in the same direction as the motion of the ball B. the normal force, pushing upward on the ball C. friction, acting in opposition to the motion of the ball D. the normal force, pulling downward on the ball
Physics
1 answer:
xeze [42]3 years ago
6 0
The answer is C. friction, acting in opposition to the motion of the ball


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An object moving north with an initial velocity of 14 m/s accelerates 5 m/s^2 for 20 seconds.what is the final velocity of the o
bekas [8.4K]

Answer:

Option C = 114 m/s

Explanation:

a=v-u/t

By substituting,

5=v-14/20

100=v-14

Thus, v=100+14

v= 114 m/s

Hope it helps :)

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Koala bears can eat only certain kinds of Australian eucalyptus leaves. Koalas are considered _____.
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A person struggles very hard to lift a large boulder. He puts in so much effort, he starts to sweat, his heart rate increases, a
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No, he did not perform any work. Work is when you’re using energy which results in a force. Even though he was tired and sweaty, he did not move the boulder. So therefore he did not perform any work.
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3 years ago
As water vapor rises into the sky it gets cold. As the water cools, water vapor is transformed into liquid water. When water cha
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2: Condensation. 4: 1,d; 2,c; 3,a; 4,e;5,b.

Explanation:

4 0
3 years ago
Three parallel wires each carry current I in the directions shown in (Figure 1). The separation between adjacent wires is d.
jasenka [17]

(a) The magnitude of the net magnetic force per unit length on the top wire is μI²/πd.

(b) The magnitude of the net magnetic force per unit length on the middle wire is zero.

(c) The magnitude of the net magnetic force per unit length on the bottom wire is 3μI²/4πd.

<h3>Force per unit length</h3>

The magnitude of the net magnetic force per unit length on the top wire is calculated as follows;

F₁/L = (μI₁/2π) x (I₂/d + I₃/d)

F₁/L = (μI/2π) x (I/d + I/d)

F₁/L = (μI/2π) x (2I/d)

F₁/L = μI²/πd

The magnitude of the net magnetic force per unit length on the middle wire is calculated as follows;

F₂/L = (μI₂/2π) x (I₃/d - I₁/d)

F₂/L = (μI/2π) x (I/d -  I/d) = 0

The magnitude of the net magnetic force per unit length on the middle bottom is calculated as follows;

F₃/L = (μI₂/2π) x (I₁/d + I₂/d)

F₃/L =  (μI/2π) x (I/2d + I/d)

F₃/L =  (μI/2π) x (3I/2d)

F₃/L =  3μI²/4πd

Thus, the magnitude of the net magnetic force per unit length on the top wire is μI²/πd.

The magnitude of the net magnetic force per unit length on the middle wire is zero.

The magnitude of the net magnetic force per unit length on the bottom wire is 3μI²/4πd.

Learn more about magnetic force here: brainly.com/question/13277365

#SPJ1

6 0
2 years ago
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