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GenaCL600 [577]
3 years ago
12

While David was riding his bike around the circular cul-de-sac by his house, he wondered if the constant circular motion was hav

ing any effect on his tires. What would be the best way for David to investigate this?
A.
Measure the circumference of the tire before and after riding.
B.
Measure the total distance traveled on his bike and divide this by how long it took him.
C.
Measure the wear on his treads before and after riding a certain number of laps.
D.
Time how long it takes him to ride 5 laps around his cul-de-sac.
Physics
1 answer:
RSB [31]3 years ago
6 0

Answer:

C.

Measure the wear on his treads before and after riding a certain number of laps.

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calculate the amount of work done when a grocery store stocker uses 120N of force to lift a sack of flour 1.5m onto a shelf
marta [7]

Hello There!

Answer is provided in the image attached.

Have a great day!

4 0
3 years ago
Now the proton at B is removed and replaced by a lithium nucleus, containing three protons and four neutrons. The proton at loca
Digiron [165]

Answer:

         F = 3 fo

Explanation:

The electric force is given by Coulomb's law

         F = k q₁ q₂ / r²

where k is the Coulomb constant and is equal to 8.99 109  

with the initial charge the force is  

        Fo = k q₁ q₂ / r²  

        Fo =k q₁ q₂ / r²

In this case it is indicated that charge 1 is changed by the lithium atom a = 3 P  

we substitute  

        F = k 3p p / r²      

        F = 3 (k p² / r²)  

        F = 3 fo

 

we see that the charge increases by three orders of magnitude

8 0
3 years ago
A uniform meter stick of mass $M$ has a half-filled can of fruit juice of mass $m$ attached to one end. The meter stick and the
notka56 [123]

Answer:

111.6 g

Explanation:

Given

m + M = 2.58 / 9.8

= 0.2632 kg

When the can of fruit juice is balance from scale , we get following relation

M x ( 50 - 21.2 ) = m x 21.2 ( balancing the torque due to weight of scale and can about the balancing point )

M x 28.8 = 21.2 m

= 21.2 ( 0.2632 - M )

= 5.58 - 21.2 M

M ( 28.8 + 21.2 ) = 5.58

M = .1116 kg

= 111.6 g

7 0
3 years ago
A balloon has a volume of 3.5-L at 25^ * C . What would be the volume of the balloon if it were placed in a container of hot wat
Romashka-Z-Leto [24]

Answer:

4.3 L

Explanation:

Ideal gas law:

PV = nRT

Rearrange:

V / T = nR / P

Since n, R, and P are constant:

V₁ / T₁ = V₂ / T₂

Plug in values and solve:

(3.5 L) / (25 + 273.15 K) = V / (95 + 273.15 K)

V = 4.3 L

5 0
3 years ago
A ball is thrown straight up into the air with an initial velocity of 50 ft/sec. The height h(t) of the ball after t seconds is
Scrat [10]

Answer:

The average velocity for the time period beginning when t=1 and lasting 0.1 seconds = 16.40 ft/s.

Explanation:

Given that the height of the ball at time t is

\rm h(t) = (50 t-16t^2)\ ft.

The average velocity of an object is defined as the total displacement covered by the particle divided by the total time taken in covering that displacement.

If \rm h_1,\ h_2 are the heights of the ball at time \rm t_1 and \rm t_2, then the total displacement covered by the ball from time \rm t_2 to \rm t_1 is \rm h_2-h_1.

Thus, the average velocity of the ball for the time interval \rm t_2-t_1  is given by

\rm v_{av}=\dfrac{h_2-h_1}{t_2-t_1}.

For the time interval, beginning when t = 1 second and lasting 0.1 seconds,

\rm t_1=1\ sec.\\t_2 = 1\sec + 0.1\ sec = 1.1\ sec.\\\\h_1=50\times 1-16\times 1^2=34\ ft.\\h_2=50\times 1.1-16\times 1.1^2=35.64\\\\Therefore,\\\\v_{av} = \dfrac{35.64-34}{1.1-1}=16.40\ ft/s.

7 0
3 years ago
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