The answer is
Ekin = 1/2 * m * v^2
Ekin = 1/2 * 5,4 * 35,2^2
Ekin = 3345,41 j (joule)
Answer:
26000 years
Explanation:
Precession describes the angular motion of the Earth's body. Since the attitude of telescopes relative to the Earth's body can be controlled with high accuracy, and telescopes can measure the direction of incoming light also with high accuracy, the motion of Earth is under permanent high precision monitoring. Thus the basic numerical descriptor of precission, an angular rate of 5029.0966 seconds of arc per Julian century, traditionally denoted p (for precession) is a measured value from observed coordinate changes of thousands of stars over, say, two centuries. The understanding of this value in terms of forces acting on an oblate Earth from the Moon is well understood so that an extrapolation back and forth over a few full cycles contains little uncertainties. Of course, you can find details on the coordinate transformations mentioned above (the direct observational effect of precession) on the net. I was surprised to see that the Wikipedia article on precession covers the astronomical aspect very poorly. You thus better look for other sources.
Answer:
7.78 * 10³ m/s
Explanation:
Orbital velocity is given as:
v = √(GM/R)
G = 6.67 * 10^(-11) Nm/kg²
M = 5.98 * 10^(24) kg
R = radius of earth + distance of the satellite from the surface of the earth
R = 2.15 * 10^(5) + 6.38 * 10^(6)
R = 6.595 * 10^(6) m
v = √([6.67 * 10^(-11) * 5.98 * 10^(24)] / 6.595 * 10^(6))
v = √(6.048 * 10^7)
v = 7.78 * 10³ m/s
Answer:
The answer is Current.
Explanation:
In a series circuit, every component will have the same <u>current</u>.
In parallel circuit, all <u>voltage</u> of component remains the same.
Answer:
1,700feet
Explanation:
If an object in free fall travels a distance s that is directly proportional to the square of the time t, this can be represented mathematically as;
S = kt²where;
k is the proportionality constant
K = s/t²
s1/t1²= s2/t2²= Sn/tn²= k for values of the distance and time. Using the formula
s1/t1² = s2/t2² where;
s1 is the falling distance in time t1 s2 is the falling distance in time t2
Given s1 = 1088feet, t1 = 8secs, s2 = ? t2 = 10secs
Substituting this value in the formula to get s2, we have;
1088/8²= s2/10²
64s2= 108800
s2 = 108800/64
s2 = 1,700feet
This means the object will fall a distance of 1,700feet in 10seconds
