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2 years ago

What happens to the force between two charges when each charge is doubled and the distance between them is 1/4 its original

Physics

1 answer:

DIA [1.3K]2 years ago

7 0

Answer:

F' = 64 F

Explanation:

The electric force between charges is given by :

$F=\dfrac{kq_1q_2}{r^2}$

Where

q₁ and q₂ are charges

r is the distance between charges

When each charge is doubled and the distance between them is 1/4 its original magnitude such that,

q₁' = 2q₁, q₂' = 2q₂ and r' = (r/4)

New force,

$F'=\dfrac{kq_1'q_2'}{r'^2}$

Apply new values,

$F'=\dfrac{k\times 2q_1\times 2q_2}{(\dfrac{r}{4})^2}\\\\=\dfrac{k\times 4q_1q_2}{\dfrac{r^2}{16}}\\\\=64\times \dfrac{kq_1q_2}{r^2}\\\\=64F$

So, the new force becomes 64 times the initial force.

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An electric flux of 147 N*m^2/C passes through a flat horizontal surface that has an area of 0.824 m^2. The flux is due to a uni

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Answer:231.16 N/C

Explanation:

Given

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Answer:

a) the pattern is bright, b) y = 8.25 mm, c) the distance increases with the wavelength increases

Explanation:

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tan θ= y / L

tan θ =sin θ/cos θ= sin θ

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c) for this part the incident light must be white or polychrome light

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y = 1 400 10⁻⁹ 1.5 / 1 10⁻³

y = 6 10⁻⁴ m

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y = 1 500 10⁻⁹ 1.5 / 1 10⁻³

y = 7.5 10⁻⁴ m

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y = 9 10⁻⁴ m

lam λ = 700 nm

y = 1 700 10⁻⁹ 1.5 / 1. 10⁻³

y = 1.05 10⁻³ m

violet, green, orange, red

the distance increases with the wavelength increases

d) To find the wavelength we must measure the distance y from the center of the slit for various interference orders and using the equation we can find the wavelength of rationality

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