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3 years ago

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A college senior who took the Graduate Record Examination exam scored 530 on the Verbal Reasoning section and 600 on the Quantit

ative Reasoning section. The mean score for Verbal Reasoning section was 460 with a standard deviation of 105, and the mean score for the Quantitative Reasoning was 429 with a standard deviation of 148. Suppose that both distributions are nearly normal. Round calculated answers to 4 decimal places unless directed otherwise.

1 answer:

erastovalidia [21]3 years ago

7 0

Answer:

Step-by-step explanation:

Given that a college senior who took the Graduate Record Examination exam scored 530 on the Verbal Reasoning section and 600 on the Quantitative Reasoning section.

Quantitative reasons scores are N (429, 148)

Hence Z score for the college senior = $\frac{530-429}{148} \\=0.6824$

The mean score for Verbal Reasoning section was 460 with a standard deviation of 105

Verbal reasoning score was N(460, 105)

The score of college senior = 530

Z score for verbal reasoning = $\frac{530-460}{105} \\=0.6667$

comparing we can say he scored more on quantiative reasoning.

Thus comparison was possible only by converting to Z scores.

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PLEASE HELP ME!!!! I NEED THIS QUICKLY!!

zloy xaker [14]

Part A: $y=-\frac{5}{4} x+\frac{35}{2}$ is the equation of the line.

Part B: Anika worked 17.5 hours on day 0.

Part C: The setup time decreases with 1 hour and 15 min per day.

Explanation:

Part A: Let us find the equation of the line using the points (2,15) and (6,10)

The equation of the line is given by,

$y-y_{1}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \cdot\left(x-x_{1}\right)$

Substituting, we get,

$y-15=\frac{10-15}{6-2} (x-2)$

Simplifying, we have,

$y-15=-\frac{5}{4} (x-2)$

$y-15=-\frac{5}{4} x+\frac{5}{2}$

Subtracting both sides by 15, we get,

$y=-\frac{5}{4} x+\frac{35}{2}$

Hence, the equation of the line is $y=-\frac{5}{4} x+\frac{35}{2}$

Part B: To determine the number of hours Anika worked on day 0, let us substitute x = 0 in the equation of the line.

Thus, we get,

$y=\frac{35}{2}\\y=17.5$

Hence, Anika worked 17.5 hours on day 0.

Part C: The setup time decrease per day can be determined using the slope.

The formula for slope is given by

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Substituting , we have,

$m=\frac{10-15}{6-2}=-\frac{5}{4}$

Converting the fraction into hours and minutes, we get,

$-\frac{5}{4}\times60=-75 min$

Since, 1 hour = 60 min

Subtracting 60 and 75 = 15 min

Thus, the setup time decreases with 1 hour and 15 min per day.

6 0

3 years ago

Jamal went to the post office to buy stamps and large envelopes. Each stamp costs the same amount, and each large envelope costs

nekit [7.7K]

Answer:

Step-by-step explanation:

i chose .95 cents!

6 0

3 years ago

Which statement is not true for a binomial distribution with n = 15 and p = 1/20 ? a) The standard deviation is 0.8441 b) The nu

malfutka [58]

Answer:

d) The highest probability occurs when x equals 0.7500

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability, given by the following formula:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

In this problem, we have that:

$n = 15, p = \frac{1}{20}$

a) The standard deviation is 0.8441

$\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{15*0.05*0.95} = 0.8441$

This is correct

b) The number of trials is equal to 15

n is the number of trials and $n = 15$ . So this option is correct.

c) The probability that x equals 1 is 0.3658

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{15,1}.(0.05)^{1}.(0.95)^{14} = 0.3658$

This option is correct.

d) The highest probability occurs when x equals 0.7500

False. The number of sucesses is a discrete number, that is, 0, 1, 2,...,15. P(X = 0.75), for example, does not exist.

e) The mean equals 0.7500

$E(X) = np = 15*0.05 = 0.75$

This option is correct.

f) None of the above

d is false

3 0

2 years ago

Evaluate - 2/5- x + (-9/10) where x = 4/5.

zalisa [80]

Answer:

- 2 1/10

Step-by-step explanation:

-2/5 -x -9/10

Let x = 4/5

-2/5 - 4/5 - 9/10

Combine like terms

-6/5 - 9/10

Get a common denominator of 10

-6/5 * 2/2 - 9/10

-12/10 - 9/10

-21/ 10

Change this to a mixed number

10 goes into 21 2 times with 1 left over

-2 1/10

6 0

3 years ago

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What is the area of the yellow square?The area of the green square is 9 ft2. The area of the red square is 16 ft2.

joja [24]

Well abnormal square would have four equal sides therefore for the firemen square since it's 9 ft^2 then u square root it and u get 3 that means each side in that green square is 3 now for the red one with 16ft^2 it would be the same consept u would square root 16 which u would get 4 now the two legs are 3 and four now u are missing the hypotenuse at c thus u use pythogerom theorom I don't know how to spell it so don't complain! You would do 3^2+4^2=c^2 which would result to 9+16=c^2. From there u would add and you would get 25 =c^2 and the reverse property of square would be square root it's that radical symbol if u remember so radical 25=5. We are still not finished we have to find the area and since we are working with normal squares where each sides ar eewual then u do 5*5 u get 25!
Now don't forget to write ft2 because then u will get it wrong
And don't be a lazy bum and try rechecking my work because I did it all in my head ok it's 12 o'clock a.m.
Peace

7 0

2 years ago

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