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Ivan
3 years ago
12

R(x)=2

="latex-formula"> s(x)=\sqrt{x} \\
Mathematics
1 answer:
dybincka [34]3 years ago
4 0
<h2>The value of (\dfrac{r}{s})(3) is equal to 2.</h2>

Step-by-step explanation:

We have,

r(x)=2\sqrt{x} and s(x)=\sqrt{x}

and (rs)(4)=8

To find, the value of (\dfrac{r}{s})(3) =?

∴ r(x)s(x)=2\sqrt{x} \sqrt{x}

(rs)(x)=2x

Also,

(\dfrac{r}{s})(x) =\dfrac{2\sqrt{x} }{\sqrt{x} }

=2

∴ The value of (\dfrac{r}{s})(3) = 2

Thus, the value of (\dfrac{r}{s})(3) is equal to 2.

You refer:

brainly.com/question/9405489

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In Rivertown High School, about 30% of the students buy a raffle ticket. Given that a student buys a raffle ticket, there is a 1
lesya [120]

The probability that that a randomly selected student will buy a raffle ticket and win a prize = 0.03

Step-by-step explanation:

Step 1 :

Given,

The percentage of students buying the raffle ticket = 30%

The percentage that the student who bought the ticket wins the prize = 10%

We need to determined the probability that randomly selected student will buy a raffle ticket and win a prize.

Step 2 :

The probability that a student buys the raffle ticket =  \frac{30}{100}  = \frac{3}{10}

The probability that a student wins a prize = \frac{10}{100} = \frac{1}{10}

The probability that a student who buys the ticket wins a price can be computed by taking the product of the above 2 probabilities.

 = \frac{3}{10} × \frac{1}{10}  = \frac{3}{100} = 0.03

Step 3 :

Answer :

The probability that that a randomly selected student will buy a raffle ticket and win a prize = 0.03

6 0
4 years ago
. If α and β are the roots of
Lostsunrise [7]

Answer:

18x^2+85x+18 = 0

Step-by-step explanation:

<u><em>Given Equation is </em></u>

=> 2x^2+7x-9=0

Comparing it with ax^2+bx+c = 0, we get

=> a = 2, b = 7 and c = -9

So,

Sum of roots = α+β = -\frac{b}{a}

α+β = -7/2

Product of roots = αβ = c/a

αβ = -9/2

<em>Now, Finding the equation whose roots are:</em>

α/β ,β/α

Sum of Roots = \frac{\alpha }{\beta } + \frac{\beta }{\alpha }

Sum of Roots = \frac{\alpha^2+\beta^2  }{\alpha \beta }

Sum of Roots = \frac{(\alpha+\beta )^2-2\alpha\beta   }{\alpha\beta  }

Sum of roots = (\frac{-7}{2} )^2-2(\frac{-9}{2} ) / \frac{-9}{2}

Sum of roots = \frac{49}{4} + 9 /\frac{-9}{2}

Sum of Roots = \frac{49+36}{4} / \frac{-9}{2}

Sum of roots = \frac{85}{4} * \frac{2}{-9}

Sum of roots = S = -\frac{85}{18}

Product of Roots = \frac{\alpha }{\beta } \frac{\beta }{\alpha }

Product of Roots = P = 1

<u><em>The Quadratic Equation is:</em></u>

=> x^2-Sx+P = 0

=> x^2 - (-\frac{85}{18} )x+1 = 0

=> x^2 + \frac{85}{18}x + 1 = 0

=> 18x^2+85x+18 = 0

This is the required quadratic equation.

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3 years ago
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3 years ago
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ankoles [38]

Answer:

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4 years ago
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Vanyuwa [196]

Answer:

x= 72

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sub 6 on both sides

then sub 3/4 (aka. 9/12)

-1/12X= -6

multiply by reciprocal (the fraction flip-flopped)(-12) on both sides

and you get 72

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3 years ago
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