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Olegator [25]
3 years ago
6

Josh is preparing for an exam by completing practice tests that have different numbers of questions. For each practice test, he

notes the number of questions and the time it takes him to complete the test.
Next, Josh creates a scatter plot and draws a trend line to fit the data. To see how well the trend line represents the data, Josh draws black lines to represent the distance each data point lies away from the trend line.



What is the sum of the residuals for all the points?

A. 97
B. 19
C. 39
D. 58

Mathematics
2 answers:
asambeis [7]3 years ago
8 0

The residuals are the numbers shown next to each black line. Just total them:


15 + 10 + 11-10 +9 +10 +3-17-12 = 19.


The answer is B. 19

motikmotik3 years ago
4 0

Answer:

The answer is B. 19

Step-by-step explanation:

HERE YOU GO THATS THE ANSWER

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The area of trapezoid TRAP is 100 m squared
Anastasy [175]
Answer:  30 m ; (or, write as: "30 meters") .
______________________________________________
Explanation:
____________________

Area of a trapezoid, "A" = (1/2) ( b₁ + b₂) h ;
______________________________________________
or, write as:  A = ( b₁ + b₂) h  / 2 ;
___________________________________
in which:  A = area;
              b₁ = length of "base 1" (choose either one of the 2 (two bases);
              b₂ = length of "base 2" (use the base that is remaining);
              h = height of trapezoid;
____________________________________________
From the information given: 
___________________________
A = 100 m² ; 
h = 5 m
b₁ = 10 m
b₂ =  x 
___________________________
Find "x", which is:  "b₂" ;
__________________________
      A = ( b₁ + b₂) h  / 2  ;
_____________________________
Plug in our known values; and plug in "x" for "b₂" ; and solve for "x" ;
_________________________________________________________
  100 m² = [(10m + x) (5m)] / 2  ; Solve for "x" ;
_________________________________________________________
          (10m + x) (5m) = (2)* (100m²) ;
_________________________________________________________
             (5m) (10m + x) = 200 m² ;
___________________________________________
Note:  The distributive property of multiplication:
____________________________________________
    a(b+c) = ab + ac ;
 
    a(b−c) = ab <span>− ac ;
</span>____________________________________________

  We have:  (5m) (10m + x) = 200 m²  ;
____________________________________________
So:    (5m) (10m + x) =  (5m*10m) + (5m * x) ;
                           
                               =  50m² + (5m)x  ;
_______________________________________________
     →  50m² + (5m)x = 200m²  ; 
_______________________________________________
Divide the ENTIRE equation by "5m" ;
_______________________________________________
     → { 50m² + (5m)x } / 5m = (200m² / 5m) ;
_______________________________________________
     →  10m + x   = 40m ; 
________________________________________________
Now, subtract "10m" from EACH side of the equation; to isolate "x" on one side of the equation; and to solve for "x" ;
_______________________________________
     →  10m + x  − 10m  =  40m − 10m ;

to get:

                →    x  =  30 m  ; which is our answer.
___________________________________________________
Answer:  30 m ; (or, write as: "30 meters") .
_____________________________________________________
6 0
3 years ago
A survey of 80 students found that 24 students both play Which of the following correctly repres
professor190 [17]

567

Step-by-step explanation:

6 0
3 years ago
Hey! Could I get a lil bit of help? (10 points)
GrogVix [38]

Answer:

<em>Neither A nor B</em>

Step-by-step explanation:

Neither set of order pairs represent a function, because none of the points have a correlating function throughout them.

4 0
3 years ago
Read 2 more answers
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Answer: The book tax is $1.10 and the video game is $3.40 so i'll let you figure this out

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6 0
3 years ago
An article presents voltage measurements for a sample of 66 industrial networks in Estonia. Assume the rated voltage for these n
kramer

Answer:

We accept the null hypothesis and conclude that voltage for these networks is 232 V.

Step-by-step explanation:

We are given the following in the question:  

Population mean, μ = 232 V

Sample mean, \bar{x} = 231.5 V

Sample size, n = 66

Sample standard deviation, s = 2.19 V

Alpha, α = 0.05

First, we design the null and the alternate hypothesis

H_{0}: \mu = 232\\H_A: \mu \neq 232

We use Two-tailed t test to perform this hypothesis.

Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n-1}} } Putting all the values, we have

t_{stat} = \displaystyle\frac{231.5- 232}{\frac{2.19}{\sqrt{66}} } = -1.8548

Now,

t_{critical} \text{ at 0.05 level of significance, 9 degree of freedom } = \pm 1.9971

Since,              

|t_{stat}| > |t_{critical}|

We accept the null hypothesis and conclude that voltage for these networks is 232 V.

4 0
3 years ago
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