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2 years ago

A)180.48 m2 B)180.48 m C)80.48 m2 D)80.48 m

Mathematics

1 answer:

MissTica2 years ago

4 0

Answer:

80.48m2

Step-by-step explanation:

I think this is right but it may be wrong.

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Suppose that on each play of a game, a gambler either wins 1 with probability p or loses 1 with probability 1–p (or q). The gamb

musickatia [10]

Answer:

Step-by-step explanation:

From the given information,

Considering both cases when p = 0.5 and when p ≠ 0.5

the probability that the gambler will quit an overall winner is:

$P = \dfrac{1 - (\dfrac{1-p}{p} )^K}{1- (\dfrac{1-p}{p})^N } \ \ \ is \ p \neq 0.5 \ and\ K/N = \dfrac{1}{2}$

where ;

N.k = n and k = m

Hence, the probability changes to:

$P = \dfrac{1 -(\dfrac{1-p}{p})^m}{1 -(\dfrac{1-p}{p})^{m+n}}$ is p ≠ 0.5 and k/N = $\dfrac{m}{m+n}$ is P = 0.5

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3 years ago

Find three fractions whose product is -5/24.

mariarad [96]

Answer:

Below.

Step-by-step explanation:

-5/8 * 1/3 = -5/24

-5/12 * 1/2 = -5/24

-5/6 * 1/4 = -5/24.

4 0

3 years ago

The manager of a local nightclub has recently surveyed a random sample of 280 customers of the club. She would now like to deter

Lunna [17]

Answer:

$z = \frac{35.6-35}{\frac{5}{\sqrt{280}}}= 2.007$

$p_v = P(z>2.007) = 0.0224$

Since the p value is lower than the significance level given of 0.05 we have enough evidence to reject the null hypothesis on this case. And the best conclusion for this case is:

We (reject) the null hypothesis. That means that we (found) evidence to support the alternative.

Step-by-step explanation:

We have the following info given:

$\bar X = 35.6$ represent the sampel mean for the age of customers

$\sigma = 5$ represent the population standard deviation

$n = 280$ represent the sample size selected

We want to test if the mean age of her customers is over 35 so then the system of hypothesis for this case are:

Null hypothesis: $\mu \leq 35$

Alternative hypothesis $\mu >35$

The statistic for this case is given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And replacing the data given we got:

$z = \frac{35.6-35}{\frac{5}{\sqrt{280}}}= 2.007$

We can calculate the p value since we are conducting a right tailed test like this:

$p_v = P(z>2.007) = 0.0224$

Since the p value is lower than the significance level given of 0.05 we have enough evidence to reject the null hypothesis on this case. And the best conclusion for this case is:

We (reject) the null hypothesis. That means that we (found) evidence to support the alternative.

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3 years ago

CAN SOMEONE MULTIPLY THIS PLEASE, ITS URGENT

____ [38]

Let's factorise it :

$\: {\qquad \dashrightarrow \sf ( {x}^{3} - 5)(x + 3) }$