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stepladder [879]
3 years ago
14

how is the rate of evporation of a liquid affected by temperature, the surface area of a liquid exposed to air

Physics
1 answer:
Debora [2.8K]3 years ago
7 0
As temperature increases, rate of evaporation also increases. This is due to increasing kinetic energy of the surface molecules which leads them to free and become vapour. c. As surface area increases, rate of evaporation also increases.
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A 0.500-kilogram cart traveling to the right on a horizontal, frictionless surface at 2.20 meters per second collides head on wi
babunello [35]

Consider the motion towards right as positive and motion towards left as negative.

m₁ = mass of the cart moving to right = 0.500 kg

v₁ = initial velocity before collision of the cart moving towards right = 2.2 m/s

m₂ = mass of cart moving to left = 0.800 kg

v₂ = initial velocity before collision of the cart moving towards left = - 1.1 m/s

initial momentum of the system of carts before the collision is given as

P₁ = m₁ v₁ + m₂ v₂

P₁ = (0.500) (2.2) + (0.800) (- 1.1)

P₁ = 0.22 kg m/s

P₂ = momentum of system of carts after collision

As per conservation of momentum,

Momentum of system of carts after collision = Momentum of system of carts before collision

P₂ = P₁

P₂ = 0.22 kg m/s



8 0
3 years ago
Which type of force is used by your legs to pedal a bicycle?
Kay [80]
The answer is strong push. When you ride a bike, the pedals convert a vertical push from your legs into rotational motion for the wheels to turn.
8 0
3 years ago
A). What is energy and its forms?
irakobra [83]

Answer:

The capacity of doing work is called energy.

its forms are :

1. mechanical energy

2.potential energy

3. kinetics energy

4. heat energy

5. light energy

6.sound energy

7. wind energy .etc.

5 0
3 years ago
Read 2 more answers
A car starts at a position of 2 km and moves to a final position of 4 km. what is the displacement of the car
Elza [17]
Should be just 2 km. - 2 km would mean it is moving in the opposite direction which come to think of it may be fine. You really can't tell.
8 0
3 years ago
Please solve this asap​
brilliants [131]

Let \vec u and \vec v be the vectors, and let x=\|\vec u\|=\|\vec v\| be their common magnitude.

The resultant \vec u + \vec v is \sqrt 2 times larger in magnitude than either vector alone, so \|\vec u+\vec v\| = \sqrt2\,x.

Recall the dot product identity

\vec a \cdot \vec b = \|\vec a\| \|\vec b\| \cos(\theta)

where \theta is the angle between the vectors \vec a and \vec b. In the special case of \vec a=\vec b, we get

\vec a \cdot \vec a = \|\vec a\|^2 \cos(0^\circ) \implies \|\vec a\| = \sqrt{\vec a\cdot\vec a}

Now, to get the angle between \vec u and \vec v, we have

\vec u \cdot \vec v = \|\vec u\| \|\vec v\| \cos(\theta) \implies \cos(\theta) = \dfrac{\vec u \cdot \vec v}{x^2}

To compute the dot product, we take the dot product of the resultant with itself.

(\vec u+\vec v) \cdot (\vec u + \vec v) = \|\vec u + \vec v\|^2

Solve for \vec u\cdot\vec v.

(\vec u\cdot\vec u) + 2(\vec u\cdot\vec v) + (\vec v\cdot\vec v) = \|\vec u + \vec v\|^2

\|\vec u\|^2 + 2(\vec u\cdot \vec v) + \|\vec v\|^2 = \|\vec u+\vec v\|^2

x^2 + 2(\vec u \cdot \vec v) + x^2 = (\sqrt2\,x)^2

2(\vec u\cdot\vec v) + 2x^2 = 2x^2

2(\vec u\cdot\vec v) = 0

\vec u\cdot\vec v = 0

Since their dot product is zero, \vec u and \vec v are perpendicular, so \theta=90^\circ.

7 0
2 years ago
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