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OleMash [197]
3 years ago
13

The velocity of a car goes from 0 m/s to 60 m/s in a forward direction. What is the best explanation for this change?

Chemistry
2 answers:
Slav-nsk [51]3 years ago
5 0

The answer is B

I'm glad I could help!

mixer [17]3 years ago
3 0
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
<span>When the velocity was 0 m/s, all the forces acting on the car were balanced. The velocity changed because at least one unbalanced force is acting on the car. </span>
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An inflatable toy starts with 1.05 moles of air and a volume of 5.17 liters. When fully inflated, the volume is 8.00 liters. If
padilas [110]

Answer:-  1.62 moles

Solution:- At constant temperature and pressure, volume is directly proportional to the moles of the gas.

\frac{V_1}{V_2}=\frac{n_1}{n_2}

from given data, V_1 = 5.17 L, n_1 = 1.05 moles

V_2 = 8.00 L, n_2 = ?

Let's plug in the values in the formula:

\frac{5.17L}{8.00L}=\frac{1.05moles}{n_2}

On cross multiply:

n_2=\frac{8.00L(1.05moles)}{5.17L}

n_2 = 1.62 moles

So, now the toy contains 1.62 moles of the air.


5 0
3 years ago
Charles's law is an experimental gas law that shows the relationship between the temperature of a gas and its corresponding volu
iren [92.7K]

Answer:

The correct answer is (b)

Explanation:

Charles law describes the behavior of gases when heated. Charles law states that the volume of a given mass of gas would increase as its Kelvin temperature increases provided the pressure is held constant. That is the volume of a given mass of gas is directly proportional to its Kelvin temperature at constant pressure

3 0
3 years ago
Be sure to answer all parts. A concentration cell consists of two Sn/Sn2+ half-cells. The electrolyte in compartment A is 0.23 M
kolbaska11 [484]

Answer:

Part A. The half-cell B is the cathode and the half-cell A is the anode

Part B. 0.017V

Explanation:

Part A

The electrons must go from the anode to the cathode. At the anode oxidation takes place, and at the cathode a reduction, so the flow of electrons must go from the less concentrated solution to the most one (at oxidation the concentration intends to increase, and at the reduction, the concentration intends to decrease).

So, the half-cell B is the cathode and the half-cell A is the anode.

Part B

By the Nersnt equation:

E°cell = E° - (0.0592/n)*log[anode]/[cathode]

Where n is the number of electrons being changed in the reaction, in this case, n = 2 (Sn goes from S⁺²). Because the half-reactions are the same, the reduction potential of the anode is equal to the cathode, and E° = 0 V.

E°cell = 0 - (0.0592/2)*log(0.23/0.87)

E°cell = 0.017V

3 0
3 years ago
Explain the meaning of the terms "saturated," "unsaturated," and "supersaturated"
dmitriy555 [2]
Saturated Solution: A solution with solute that dissolves until it is unable to dissolve anymore, leaving the undissolved substances at the bottom. Unsaturated Solution: A solution ( with less solute than the saturated solution )that completely dissolves, leaving no remaining substances. Supersaturated Solution.
5 0
2 years ago
2. Which of the most abundant elements in Earth's crust are nonmetals?​
melisa1 [442]

Answer:

it is oxygen

Explanation:

4 0
3 years ago
Read 2 more answers
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