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3 years ago

3,010,000 into scientific notation

Chemistry

2 answers:

sdas [7]3 years ago

6 0

Answer:

3.01 x 10^6

Explanation:

We start at the farthest right of this number, then shifting it 6 places to the left until we get only one whole digit in our answer. In this case are whole digit would be the number "3" from the millions place written out as 3.01 x 10^6. Because we started at the right of the number and shifted to the left 6 times, we get a positive exponent of "6."

Here is an example of a negative exponent in scientific notation:

skelet666 [1.2K]3 years ago

3 0

Answer:

3.01 x 10 to the power of 6

Explanation:

Step 1

To find a, take the number and move a decimal place to the right one position.

Original Number: 3,010,000

New Number: 3.010000

Step 2

Now, to find b, count how many places to the right of the decimal.

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If 42.8 mL of 0.204 M HCl solution is needed to neutralize a solution of Ca(OH)2, how many grams of Ca(OH)2 must be in the solut

Aneli [31]

Hey There!

At neutralisation moles of H⁺ from HCl = moles of OH⁻ from Ca(OH)2 so :

0.204 * 42.8 / 1000 => 0.0087312 moles

Moles of Ca(OH)2 :

2 HCl + Ca(OH)2 = CaCl2 + 2 H2O

0.0087312 / 2 => 0.0043656 moles ( since each Ca(OH)2 ives 2 OH⁻ ions )

Therefore:

Molar mass Ca(OH)2 = 74.1 g/mol

mass = moles of Ca(OH)2 * molar mass

mass = 0.0043656 * 74.1

mass = 0.32 g of Ca(OH)2

Hope that helps!

6 0

3 years ago

Predict the products of La(s) + O2(aq) ->

mina [271]

Answer:

i. La (s) + O2 (g) => LaO2 (s)

ii. La (s) + O2 (g) => La2O (s)

III. La (s) + O2 (g) => La2O3 (s)

Explanation:

Hello there!

When you are given such a problem for completing the chemical equations, what you have to understand is that metals are found in groups I, II and III. While Oxygen is a group VI element.

From the above question I have considered that my La(s), solid is either Sodium (Na) - group I, Magnesium - group II and Aluminum - group III.

In a reaction, there is exchange of electrons given by their oxidation numbers (I, II and III - for our metals above)

The chemical equations are thus;

i. Na (s) + O2 (g) => NaO (s)

ii. Mg (s) + O2 (g) => Mg2O (s)

iii. Al (s) + O2 (g) => Al2O3 (s)

Relate this to the problem and it will be;

i. La (s) + O2 (g) => LaO2 (s)

ii. La (s) + O2 (g) => La2O (s)

III. La (s) + O2 (g) => La2O3 (s)

I hope this helps you to understand better. Enjoy your studies

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2 years ago

Enter a balanced equation for the reaction between solid nickel(II)(II) oxide and carbon monoxide gas that produces solid nickel

velikii [3]

Answer: A balanced equation for the given reaction is $NiO(s) + CO \rightarrow Ni(s) + CO_{2}(g)$ .

Explanation:

The reaction equation will be as follows.

$NiO(s) + CO \rightarrow Ni(s) + CO_{2}(g)$

Number of atoms on the reactant side is as follows.

O = 2
C = 1

Number of atoms on the product side is as follows.

Ni = 1
O = 2
C = 1

Since number of atoms on both the reactant and product sides are equal. Hence, the reaction equation is balanced.

Thus, we can conclude that a balanced equation for the given reaction is $NiO(s) + CO \rightarrow Ni(s) + CO_{2}(g)$ .

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3 years ago

Adding more than one equivalent of HCl to pent-1-yne will lead to which product:______.

Ket [755]

Answer:

c. 2,2-dichloropentane.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to firstly draw the structure of the reactant, pent-1-yne:

$CH\equiv C-CH_2-CH_2-CH_2$

Now, we infer the halogen is added to the carbon atom with the most carbon atoms next to it, in this case, carbon #2, in order to write the following product:

$CH\equiv C-CH_2-CH_2-CH_2+2HCl\rightarrow CH_3- CCl_2-CH_2-CH_2-CH_2$

Whose name is 2,2-dichloropentane.

Regards!

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Alla [95]

Answer:

Hello

I am Parth

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2 years ago