All categories

2 years ago

3,010,000 into scientific notation

Chemistry

2 answers:

sdas [7]2 years ago

6 0

Answer:

3.01 x 10^6

Explanation:

We start at the farthest right of this number, then shifting it 6 places to the left until we get only one whole digit in our answer. In this case are whole digit would be the number "3" from the millions place written out as 3.01 x 10^6. Because we started at the right of the number and shifted to the left 6 times, we get a positive exponent of "6."

Here is an example of a negative exponent in scientific notation:

skelet666 [1.2K]2 years ago

3 0

Answer:

3.01 x 10 to the power of 6

Explanation:

Step 1

To find a, take the number and move a decimal place to the right one position.

Original Number: 3,010,000

New Number: 3.010000

Step 2

Now, to find b, count how many places to the right of the decimal.

You might be interested in

Naoki's bicycle has a mass of 11 kg. If Naoki sits on her bicycle and starts pedaling with a force of 197.2 N, causing an accele

Cloud [144]

yes 89.75 sorry I'm not the best at math you should look on the internet

7 0

2 years ago

In 1865 a pond was surrounded by open fields today the same area is swampy and surrounded by a forest which process is responsib

Nookie1986 [14]

Answer:

erosion

Explanation:

3 0

2 years ago

Read 2 more answers

A solution made by dissolving 33 mg of insulin in 6.5 mL of water has an osmotic pressure of 15.5 mmHg at 25°C. Calculate the mo

Liula [17]

<u>Answer:</u> The molar mass of the insulin is 6087.2 g/mol

<u>Explanation:</u>

To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

$\pi=iMRT$

Or,

$\pi=i\times \frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}\times RT$

where,

$\pi$ = osmotic pressure of the solution = 15.5 mmHg

i = Van't hoff factor = 1 (for non-electrolytes)

Mass of solute (insulin) = 33 mg = 0.033 g (Conversion factor: 1 g = 1000 mg)

Volume of solution = 6.5 mL

R = Gas constant = $62.364\text{ L.mmHg }mol^{-1}K^{-1}$

T = temperature of the solution = $25^oC=[273+25]=298K$

Putting values in above equation, we get:

$15.5mmHg=1\times \frac{0.033\times 1000}{\text{Molar mass of insulin}\times 6.5}\times 62.364\text{ L.mmHg }mol^{-1}K^{-1}\times 298K\\\\\text{molar mass of insulin}=\frac{1\times 0.033\times 1000\times 62.364\times 298}{15.5\times 6.5}=6087.2g/mol$