All categories

1 year ago

Analyze How would tides be affected if the Moon was farther away from Earth?

Chemistry

2 answers:

strojnjashka [21]1 year ago

6 0

Answer: The farther away the moon is from earth the lower the tides would be.

Explanation: Because of the moons close proximity to Earth its gravity pulls up on water which causes the high and low tides, therefore if the moon is farther away its effect would be lessened.

trasher [3.6K]1 year ago

4 0

Answer:

Explanation:

Newton's law of gravity says that the attractive gravitational force is inversely proportional to the square of distance between two objects.

Earth tidal force is due to gravity pull from the Moon. That is why tides follow a monthly cycle according to the position of the Moon. If the Moon was farther away from Earth, tidal waves will be reduced.

You might be interested in

what tool do you have to use to precise amount of water? A meter stick B stopwatch C balance D graduated cylinder E beaker F the

Serhud [2]

Answer:

graduated cylinder

Explanation:

It shows exact volume very precisely.

8 0

2 years ago

What is the volume of a 5.30g piece of aluminum? The density for aluminum is 2.70mL

Makovka662 [10]

Answer:

1.96mL

Explanation:

Density = mass/volume, and rearranged to solve for volume, volume = mass/density.

So:

volume = 5.30g/2.70g/mL = 1.96mL (assuming your unit was g/mL for density)

7 0

2 years ago

Topics: Fundamentals of electrochemistry; Electrochemical cells

irina1246 [14]

Answer:

how to help people that helps

5 0

2 years ago

A manganese electrode was oxidized electrically. If the mass of the electrode decreased by 225 mg during the passage of 1580 cou

qwelly [4]

Answer:

<u>Oxidation state of Mn = +4</u>

Explanation:

Atomic mass of Mn = 55g/mol

From Faraday's law of electrolysis,

Electrochemical equivalent = $\frac{mass}{charge}$

i.e Z = $\frac{m}{Q}$ = $\frac{0.225g}{1580C}$ = 0.0001424 g/C

But Equivalent weight, E = atomic mass ÷ valency = Z × 96,485

⇒ $\frac{55}{valency}$ = 0.0001424 × 96,485

<u>∴ Valency of Mn = +4</u>

8 0

2 years ago

If a 100. -g sample of a hydrated compound contains 37.07-g sodium, 48.39-g carbonate and 14.54-g water, find the empirical form

Mumz [18]

he required empirical formula based on the data provided is Na2CO3.H2O.

<h3>What is empirical formula?</h3>

The term empirical formula refers to the formula of a compound which shows the ratio of each specie present.

We have the following;

Mass of sodium = 37.07-g

Mass of carbonate = 48.39 g

Mass of water = 14.54-g

Number of moles of sodium = 37.07-g/23 g/mol = 2 moles

Number of moles of carbonate = 48.39 g/61 g/mol = 1 mole

Number of moles of water = 14.54/18 g/mol = 1 mole

The mole ratio is 2 : 1: 1

Hence, the required empirical formula is Na2CO3.H2O

Learn more about empirical formula : brainly.com/question/11588623

3 0

1 year ago