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2 years ago

Analyze How would tides be affected if the Moon was farther away from Earth?

Chemistry

2 answers:

strojnjashka [21]2 years ago

6 0

Answer: The farther away the moon is from earth the lower the tides would be.

Explanation: Because of the moons close proximity to Earth its gravity pulls up on water which causes the high and low tides, therefore if the moon is farther away its effect would be lessened.

trasher [3.6K]2 years ago

4 0

Answer:

Explanation:

Newton's law of gravity says that the attractive gravitational force is inversely proportional to the square of distance between two objects.

Earth tidal force is due to gravity pull from the Moon. That is why tides follow a monthly cycle according to the position of the Moon. If the Moon was farther away from Earth, tidal waves will be reduced.

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What is the formula of the ion formed when tin achieves a stable electron configuration?

Katarina [22]

Answer:

Option D which is Sn4- is the answer

4 0

3 years ago

A 51.24-g sample of Ba(OH)2 is dissolved in enough water to make 1.20 liters of solution. How many mL of this solution must be d

g100num [7]

Answer:

0.40 L

Explanation:

Calculation of the moles of $Ba(OH)_2$ as:-

Mass = 51.24 g

Molar mass of $Ba(OH)_2$ = 171.34 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{51.24\ g}{171.34\ g/mol}$

$Moles= 0.2991\ mol$

Volume = 1.20 L

The expression for the molarity is:

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

$Molarity=\frac{0.2991\ mol}{1.20\ L}=0.24925\ M$

Thus,

Considering

$Molarity_{working\ solution}\times Volume_{working\ solution}=Molarity_{stock\ solution}\times Volume_{stock\ solution}$

Given that:

$Molarity_{working\ solution}=0.100\ M$

$Volume_{working\ solution}=1\ L$

$Volume_{stock\ solution}=?$

$Molarity_{stock\ solution}=0.24925\ M$

So,

$0.100\ M\times 1\ L=0.24925\ M\times Volume_{stock\ solution}$

$Volume_{stock\ solution}=\frac{0.100\times 1}{0.24925}\ L=0.40\ L$

<u>The volume of 0.24925M stock solution added = 0.40 L </u>

6 0

3 years ago

You come home and find that there's been a power outage while food was cooking in the slow cooker. What should you do wit the fo

klasskru [66]

Answer:

Well you can not serve it because it is a slow cooker it cooks slow and the refrigerator uses power.Stove tops use power too, I wouldn't feed it to the dog because it whatever you made could possibly make the dog sick and throwing it away is a waste of money. Out of all of those explanations choose the best one. Which ever one you pick whether right or wrong, think about it.

Explanation:

7 0

3 years ago

Name the compounds( Please answer only if you know)

IRISSAK [1]

Answer

2-methyl-2-pentene

Explanation:

1. Identify the group that takes precedence in this case alkene hence this molecule is an alkene with a methyl group side chain.

2.Find the longest carbon chain where the functional group(alkene group in this case) has the lowest Carbon number

3.What are the side groups? One side group can be seen at carbon 2 this group is methyl

4. Naming, number separated by "," and number from letters by "-" so the compound should be

2-methyl-2-pentene

8 0

3 years ago

A container of oxygen with a fixed volume has a pressure of 13.0 atm at a temperature of 20 °C. What will the pressure of the ox

Norma-Jean [14]

Given:

P1 = 13.0 atm

T1 = 20 °C

T2 = 102 °C

Required:

P2 of oxygen

Solution:

At constant volume, we can apply Gay-Lussac’s law of pressure and temperature relationship

P1/T1=P2/T2

(13.0 atm) / (20 °C) = P2 / (102 °C)

P2 = 66.3 atm

The answer is not in the choices given.

6 0

3 years ago