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pashok25 [27]
3 years ago
13

2C4H10 + 13O2 --> 8CO2 + 10H2O

Chemistry
1 answer:
lutik1710 [3]3 years ago
7 0
This is the combustion reaction of butane which releases energy
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True or false questions?
egoroff_w [7]

Answer:

1. False 2.True3.True? Unsure

Explanation:

8 0
3 years ago
Predict the products of the double replacement reaction 2KOH + H2504 --?
Darina [25.2K]
What the heck is this 9287262729272727272727171
4 0
3 years ago
HURRY FOR A TEST! The ionization energies for removing successive electrons from sodium are 496 kJ/mol, 4562 kJ/mol,
prohojiy [21]

Answer:

D. The noble gas configuration has been reached.

Explanation:

8 0
3 years ago
What type of reaction will occur with the following reactants?
zalisa [80]

Answer:

A) double replacement

Explanation:

Chemical equation:

NaCl +CaS    →    Na₂S + CaCl₂

Balanced chemical equation:

2NaCl +CaS    →    Na₂S + CaCl₂

The given reaction is double replacement reaction in which cation and anions of each reactant exchange with each other.

Double replacement:

It is the reaction in which two compound exchange their ions and form new compounds.

AB + CD → AD +CB

Other options are incorrect because,

Synthesis reaction:

It is the reaction in which two or more simple substance react to give one or more complex product.

AB → A + B

Single replacement:

It is the reaction in which one elements replace the other element in compound.

AB + C → AC + B

Decomposition reaction:

It is the reaction in which one reactant is break down into two or more product.

AB → A + B

6 0
3 years ago
A quantity of monatomic ideal gas expands adiabatically from a volume of 2.0 liters to 6.0 liters. if the initial pressure is p0
alukav5142 [94]

Answer:

1/3p0

Explanation:

The combined gas law:

P1V1/T1 = P2V2/T2, where P, V and T are Pressure, Volume, and Temperature.  Temperature must always be in Kelvin.  The subscriopts 1 and 2 are for initial (1) and final (2) conditions.

In this case, temperature is constant (adiabatically). V1 = 2.0L and V2 = 6.0L.  I'll assume P1 = p0.

Rearrange the combined gas law to solve for final pressure, P2:

P1V1/T1 = P2V2/T2

P2 = P1*(V1/V2)*(T2/T1)  [Note how I've arranged the volume and temoperature terms - as ratios.  This helps us understand what the impact of raising or lowering one on the variables will do to the system].

No enter the data:

P2 = P1*(V1/V2)*(T2/T1):  [Since T2 = T1, the (T2/T1) terms cancels to 1.]

P2 = p0*(2.0L/6.0L)*(1)

P2 = (1/3)p0

The final pressure is 1/3 the initial pressure.

7 0
2 years ago
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