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fenix001 [56]
3 years ago
10

PLEASE HELP

Chemistry
1 answer:
Art [367]3 years ago
3 0
1)water has a great capacity to hold a moderate heat energy
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A compound contains 1.2 g of carbon, 3.2 g of oxygen and 0.2g of hydrogen. Find the formula of the compound
Karolina [17]

Answer:

The empirical formula of the compound is C_{0.504}HO_{1.008}.

Explanation:

We need to determine the empirical formula in its simplest form, where hydrogen (H) is scaled up to a mole, since it has the molar mass, and both carbon (C) and oxygen (O) are also scaled up in the same magnitude. The empirical formula is of the form:

C_{x}HO_{y}

Where x, y are the number of moles of the carbon and oxygen, respectively.

The scale factor (r), no unit, is calculated by the following formula:

r = \frac{M_{H}}{m_{H}} (1)

Where:

m_{H} - Mass of hydrogen, in grams.

M_{H} - Molar mass of hydrogen, in grams per mole.

If we know that  M_{H} = 1.008\,\frac{g}{mol} and m_{H} = 0.2\,g, then the scale factor is:

r = \frac{1.008}{0.2}

r = 5.04

The molar masses of carbon (M_{C}) and oxygen (M_{O}) are 12.011\,\frac{g}{mol} and 15.999\,\frac{g}{mol}, then, the respective numbers of moles are: (r = 5.04, m_{C} = 1.2\,g, m_{O} = 3.2\,g)

Carbon

n_{C} = \frac{r\cdot m_{C}}{M_{C}} (2)

n_{C} = \frac{(5.04)\cdot (1.2\,g)}{12.011\,\frac{g}{mol} }

n_{C} = 0.504\,moles

Oxygen

n_{O} = \frac{r\cdot m_{O}}{M_{O}} (3)

n_{O} = \frac{(5.04)\cdot (3.2\,g)}{15.999\,\frac{g}{mol} }

n_{O} = 1.008\,moles

Hence, the empirical formula of the compound is C_{0.504}HO_{1.008}.

3 0
3 years ago
When a current is passed through a solution of salt water, sodium chloride decomposes according to the following reaction:
murzikaleks [220]
The answers are the following:
1.B 35.45
2.B 70.90
7 0
4 years ago
Read 2 more answers
How do you think dry cleaning works?
andriy [413]
<h2><em><u>During dry cleaning, the pump pulls solvent from the tank and sends it through the filters to remove any impurities. The filtered solvent then enters the cylinder, where it interacts with the fabrics and removes any soil. The solvent then travels back into the holding tank so it can begin the process again.</u></em></h2>

<em><u>mark</u></em><em><u> </u></em><em><u>this </u></em><em><u>as</u></em><em><u> a</u></em><em><u> </u></em><em><u>brainliest</u></em>

6 0
3 years ago
Complete the equation and indicate if a precipitate forms.
Novosadov [1.4K]

Answer:

Li⁺(aq) + 2Br⁻(aq) + Pb²⁺(aq) + NO₃⁻(aq) → PbBr₂(s) + NO₃⁻(aq) + Li⁺(aq)

A precipitate forms

Explanation:

To solve this question we must know the general solubility rules:

All group 1A (Li, Na, K...) and NH₄⁺ ions are always soluble.

The nitrates (NO₃⁻) and acetates are always solubles.

Cl⁻, Br⁻ and I⁻ are soluble except in the presence of Ag⁺, Pb²⁺, Cu⁺ and Hg₂²⁺

That means in the mixture of ions that we have, the Br⁻ will react with Pb²⁺ to produce PbBr₂(s):

<h3>Li⁺(aq) + 2Br⁻(aq) + Pb²⁺(aq) + NO₃⁻(aq) → PbBr₂(s) + NO₃⁻(aq) + Li⁺(aq) </h3>

8 0
3 years ago
1. How many grams of Mg(OH)2 are there in 4.5 moles?
Ket [755]

Answer:

1) 262 grams

Explanation:

Mg = 24.305g

O = 16g

H = 1

24.305 +2(16)+2(1) = 58.305 g

×\frac{58.305g}{1} = \frac{x }{4.5 } =262.37 g

7 0
3 years ago
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