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lbvjy [14]
3 years ago
12

I need help please someone !!!!! Would appreciate it

Physics
1 answer:
babymother [125]3 years ago
5 0

Answer:

Yes, it would make it back up.

Explanation:

If it has 100,000 Joules of gravitational potential energy at the top of the hill, by the time the cart gets to the bottom, it will become PE = 0, KE = 90,000 since 10% of 100,000 is 10,000. The cart only requires 80,000J to climb back up so it should easily do so.

I didn't quite understand if the 10% energy loss is total, or every time it goes up or down, but it isn't a problem because 10% of 90,000 is 9,000, which means it would have 81,000J of energy on the way back up IF it loses energy due to friction on the way back up also.

The only physical law you need to prove this is the Law of Conservation of Energy: no energy is lost, only transformed; 10% of the energy becomes heat, the rest remains mechanical energy, which is the reason why the reasoning above works.

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It is about a billion times brighter.

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2 years ago
A highway patrolman traveling at the speed limit is passed by a car going 20 mph faster than the speed limit. After one minute,
Oksi-84 [34.3K]

Answer:

It will take 40 seconds to catch the speeding car

Explanation:

Initial speed of the patrolman = 55 mph

after one minute speed of patrol man = 115 mph

now acceleration of patrolman is given by

a = \frac{v_f - v_i}{t}

a = \frac{115 - 55}{1/60} = 3600 m/h^2

now at this acceleration the distance covered by patrolman in "t" time is given as

d = v_i t + \frac{1}{2}at^2

d = 55t + 1800t^2

now we know the speed of the speeding car is given as

v' = (55+20) mph

now in the same time distance covered by it

d = 75 t

now since the distance covered is same

75 t = 55t + 1800 t^2

t = \frac{20}{1800} = \frac{1}{90} h

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4 years ago
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When a bar magnet is thrust into a coil of copper wire the wire wll produce magnetic field taht?
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The driver of a pickup truck accelerates from rest to a speed of 37 mi/hr over a horizontal distance of 215 ft with constant acc
Alona [7]

Answer:

Maximum shearing force developed in each of the two pegs during acceleration is 1830 lbf

Explanation:

First we will find the acceleration of pickup truck.

As, the acceleration is uniform, therefore we can use Newton's third equation of motion:

2as = V_{f}^{2}-V_{i}^{2}

First convert speed into ft/sec

1 mile/hr = 1.47 ft/sec

therefore,

37 mile/hr = 37 x 1.47 ft/sec

37 mile/hr =  54.39 ft/sec

with initial speed 0 ft/sec (starting from rest), using in equation of motion:

a = [(54.39 ft/sec)² - (0 ft/sec)²]/2(215 ft)

a = 6.88 ft/sec²

Now, the total shear force will be given by Newton's second law of motion:

F = ma

F = (460 lbm +72 lbm)(6.88 ft/sec²)

F = 3660 lbf

Now for the max shear force in each of the two pegs we divide total fore by 2:

Force in each peg = F/2 = (3660 lbf)/2

<u>Force in each peg = 1830 lbf</u>

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Is it possible for an atom to have an electric charge?
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