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lbvjy [14]
3 years ago
12

I need help please someone !!!!! Would appreciate it

Physics
1 answer:
babymother [125]3 years ago
5 0

Answer:

Yes, it would make it back up.

Explanation:

If it has 100,000 Joules of gravitational potential energy at the top of the hill, by the time the cart gets to the bottom, it will become PE = 0, KE = 90,000 since 10% of 100,000 is 10,000. The cart only requires 80,000J to climb back up so it should easily do so.

I didn't quite understand if the 10% energy loss is total, or every time it goes up or down, but it isn't a problem because 10% of 90,000 is 9,000, which means it would have 81,000J of energy on the way back up IF it loses energy due to friction on the way back up also.

The only physical law you need to prove this is the Law of Conservation of Energy: no energy is lost, only transformed; 10% of the energy becomes heat, the rest remains mechanical energy, which is the reason why the reasoning above works.

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3 years ago
"A grinding wheel with a moment of inertia of 2.0 kg-m2 has a 2.5 N-m torque applied to it. What is its final kinetic energy 10
amid [387]

Answer:

Ek = 156.25 J

Explanation:

Given:-

- The moment of inertia of the grinding wheel I = 2.0 kg-m2

- The torque applied T = 2.5 N-m

Find:-

What is its final kinetic energy 10 seconds after starting from rest?"

Solution:-

- The relationship between applied torque and the angular acceleration α of the grinding wheel is can be expressed as:

                                       T = I*α

- Solve for α , using the given data:

                                       2.5 = 2.0*α

                                       α = 1.25 rad / s^2

- Assuming constant acceleration ( constant applied torque T ) we can determine the angular velocity of the grinding wheel after time t = 10 sec using rotational kinematic equation of motion.

                                      wf = wi + α*t

Where, wf = Final angular velocity (rad/s)

            wi = Initial angular velocity (rad/s)

- Assuming the grinding wheel was initially at rest wi = 0 rad /s. We have:

                                     wf = 0 + 1.25*10

                                     wf = 12.5 rad/s

- The kinetic energy (Ek) of the grinding wheel after 10 seconds can b determined in rotational kinematics terms as follows:

                                     Ek = 0.5*I*wf^2

                                     Ek = 0.5*2.0*12.5^2

                                    Ek = 156.25 J

- The kinetic energy of the grinding wheel after 10 seconds is Ek = 156.25 J

4 0
4 years ago
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