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77julia77 [94]
3 years ago
13

4. Explain why 50 g of liquid water at 0°C heats-up more quickly than 50 g of an ice water mixture at 0°C under the same conditi

ons.
5. How much energy (in kilocalories, kcal) is needed to melt 33.8 g of ice at 0.0°C?
6. How much energy (in kilocalories, kcal) is needed to warm 33.8 g of liquid water from 0.0°C to 37.0°C?

PLEASE HELP WITH ALL 3 NUMBERS 4,5,6
Chemistry
1 answer:
Minchanka [31]3 years ago
5 0
4) the ice has to be heated up to above 0c first, as it is continuing to cool the water back toward 0c
5) 0.0338 kcal
(33.8/1000)
6) 1.2506 kcal
((33.8*37.0)/1000)
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The mass number of an atom is 15, and its atomic number is 7. The atom probably has... 8 neutrons in the nucleus. about as much
Artist 52 [7]

Answer: Option (a) is the correct answer.

Explanation:

Atomic number is the sum of only total number of protons present in an element. Whereas mass number is the sum of total number of both protons and neutrons present in an element.

For example, given atom has mass number as 15 and its atomic number is 7.

Therefore, number of neutrons present in it will be calculated as follows.

                    Mass number = no. of protons + no. of neutrons

                         15 = 7 + no. of neutrons

                    no. of neutrons = 15 - 7

                                               = 8

Thus, we can conclude that the given atom contains 8 neutrons in the nucleus.

3 0
3 years ago
Need helpppp please
Vladimir79 [104]

Answer:

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Explanation:

6 0
2 years ago
How many liters of C3H6O are present in a sample weighing 25.6 grams?
Romashka [77]

Answer:

V = 0.0327 L.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to calculate the liters of C3H6O by the definition of density. We can tell the density of this substance as that of acetone (0.784 g/mL) and therefore calculate the liters as shown below:

V=25.6g*\frac{1mL}{0.784g}*\frac{1L}{1000mL}\\\\V=0.0327L

Regards!

7 0
3 years ago
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The oxidation is occurring on Calcium ions as it release one electron and reduction will be occurring on fluorine ion as it accepts one electron.

<u>Explanation:</u>

An element will undergo oxidation and form a positive ion on releasing one or more electrons from its valence shell. While reduction is occurred in a chemical reaction, then the element will be forming a negative ion with the acceptance of one or more electrons in its valence shell.

So in the given process of calcium fluoride, the one electron from the valence shell of calcium will be released making it as c a^{+} ions and this is termed as oxidation process. This one electron will be getting accepted by the fluorine ion and thus it will convert to F^{-} ions. This process of acceptance of electrons is termed as reduction.

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