Yes! You're correct! Hope this helps! :D
Based on the assumption that the reaction involves N and O to produce NO, if 25.0 g of NO are produced, the amount of N gas used would be 11.66 grams
<h3>Stoichiometric calculation</h3>
From the equation of the reaction:
N + O ---------> NO
Mole ratio of N to NO is 1:1
Mole of 25.0 g of NO = 25/30.01 = 0.833 moles
Equivalent mole of N = 0.833 moles
Mass of 0.833 moles N = 0.833 x 14 = 11.66 grams
More on stoichiometric calculations can be found here: brainly.com/question/8062886
Answer:
A beta particle
Explanation:
The radioactive particle must undergo a beta decay to have the mass number unchanged but the atomic number to have decreased by one.
This type of beta decay results in the emission of a positron which is a type of beta particle. It resembles an electron but it has a positive charge of 1.
Answer:
18.9 moles of MgCl2 = 17.834 kg of MgCl2
Explanation:
The molecular weight of MgCl is 80.0 g/mol . So, to convert the given mole amount to grams, multiply this by this number, which is constant for all compounds with a specific composition (mass fraction).
Considering the original question was in the context of chemistry, I wanted to make it seem formal and more educational too. Hopefully that worked!
EDIT: Came up with some text around what happens inside cells that would have made it better if someone just had an issue converting units, but I doubt my answer will be accepted >.<
Work out the number of moles in
100.00 grams of the oxide.
For nitrogen: The atomic mass of N is 14.0067, and we have 36.84 g N:
36.84 g N14.0067 g N/mol N=2.630 mol N
For oxygen: The atomic mass of O is
15.9994, and we have
100.00−36.84=63.16 g O:
63.16 g N 15.9994 g N/mol N=3.948 mol N
Now the ratio 3.958 2.630 is very close to
1.5=32
. So we conclude that the gas has three moles
O to two moles N making the empirical formula
N2O3.
<h2>
<u>Mark as Brainliest</u></h2>