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3 years ago

15

Rebecca is wrapping identical gifts each gift uses 3 1/3 ft of ribbon the roll of ribbon is 25 ft long what is the greatest numb

er of gift she could wrap with the ribbon

1 answer:

Anika [276]3 years ago

7 0

Rebecca can rap 7 gifts in all.

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Can someone please help me

DaniilM [7]

Answer:

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Step-by-step explanation:

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3 0

3 years ago

Arrange the following in decreasing order. 3.8 m^2 380 cm? 0.038 km2 3,800 mm Which of the following shows the answers in decrea

Snezhnost [94]

Answer:

C. 0.038 km² > 3.8 m² > 380 cm² > 3800 mm²

Step-by-step explanation:

Convert every measurement to the same unit, say, square metres.

(a) 3.8 m²

No conversion necessary

(b) 380 cm²

$\text{Area} = \text{380 cm}^{2} \times \left (\dfrac{\text{1 m}}{\text{100 cm}} \right )^{2} = \textbf{0.038 m}^{2}$

(c) 0.038 km²

$\text{Area} = \text{0.038 km}^{2} \times \left (\dfrac{\text{1000 m}}{\text{1 km}} \right )^{2} = \textbf{38 000 m}^{2}$

(d) 3800 mm²

$\text{Area} = \text{3800 mm}^{2} \times \left (\dfrac{\text{1 m}}{\text{1000 mm}} \right )^{2} = \textbf{0.0038 m}^{2}$

In decreasing order, 0.038 km² > 3.8 m² > 380 cm² > 3800 mm²

6 0

2 years ago

A pyramid has a regular hexagonal base with side lengths of 4 and a slant height of 6. Find the total area of the pyramid.

Tanzania [10]

The total area of pyramid is 113.569 square units

The equation to find the total area of the pyramid is Total area = base area + lateral area.

<u>Solution:</u>

Given, A pyramid has a regular hexagonal base with side lengths of 4 and a slant height of 6.

<em><u>The total area of pyramid is given by:</u></em>

$A=A_{b}+A_{l}$ ---- eqn 1

Where,

$A_{b} \text { is the base area and } A_{l} \text { is the lateral area }$

<em><u>The area of base is given as:</u></em>

$A_{b}=\frac{3 \sqrt{3}}{2} l^{2}$

Where "l" is the side of hexagon.

Substituting we get,

$\begin{array}{l}{A_{b}=\frac{3 \sqrt{3}}{2}(4)^{2}} \\\\ {=\frac{3 \sqrt{3}}{2} \times 16=3 \sqrt{3} \times 8} \\\\ {A_{b}=24 \sqrt{3}}\end{array}$

<em><u>The lateral area is given as:</u></em>

$A_{l}=3 b h$

Where,

b: base of the triangle

h: height of the triangle

Substituting we get,

$\begin{array}{l}{A_{l}=3 \times(4) \times(6)} \\\\ {A_{l}=72}\end{array}$

Plugging in the values we found in eqn 1 we get,

$A=24 \sqrt{3}+72$

A = 113.569 square units

<em><u>Summarizing the results:</u></em>

The total area of pyramid is 113.569 square units approximately

The equation used to find total area of pyramid is Total area = base area + lateral area.

8 0

2 years ago

Whats the distance between points p(8,2) and q(3,8)

True [87]

The answer is 7.8
Hope this helps!

8 0

3 years ago

The rectangular backboard of a basketball court needs to be assembled. Its area is given as 18,900 cm2 and the width as 1.8 m.

boyakko [2]

18900cm = 189m
189 / 1.8 = 105m.

The blackboard's length in meters is 105m.

3 0

3 years ago

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