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3 years ago

15

Rebecca is wrapping identical gifts each gift uses 3 1/3 ft of ribbon the roll of ribbon is 25 ft long what is the greatest numb

er of gift she could wrap with the ribbon

1 answer:

Anika [276]3 years ago

7 0

Rebecca can rap 7 gifts in all.

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How many edges must be removed from the wheel graph W6 in order to create a spanning tree for the graph?

sveticcg [70]

Answer:

The correct option is A.

Step-by-step explanation:

If a graph is formed by connecting a single universal vertex to all vertices of a cycle, then it is known as wheel graph.

W₆ means wheel graph having 6 vertices as shown in the below figure.

Total number of edges in a wheel graph is 2(n-1), where n is number of vertices. So, the number of edges in W₆ is

$2(6-1)=10$

In a spanning tree all the vertices covered with minimum possible number of edges. Total number of edges in a spanning tree is (n-1).

Total number of edges in a spanning tree which has 6 vertices is

$6-1=5$

The number of edges we need to remove is

$10-5=5$

Therefore the correct option is A.

5 0

3 years ago

For what value of x is sin x = cos 19º, where 0°< x < 90°?

KonstantinChe [14]

Answer:

71°

Step-by-step explanation:

The cosine of an angle is equal to the sine of its complement:

cos(19°) = sin(90° -19°) = sin(71°)

Comparing to the given expression, we see that x = 71°.

7 0

3 years ago

Arlene us showing her work in simplifying(−7.9)+8.2−3.4+2.1 identify any error in her work or in her reasoning.

Brums [2.3K]

Keep doing each step manually, and see where it slips up: −7.9+8.2−3.4+2.1=−1 −7.9+8.2+(−3.4)+2.1=−1 −7.9+(−3.4)+8.2+2.1=−1 (−7.9+(−3.4))+(8.2+2.1)=−1 −11.3+10.3=−1

4 0

3 years ago

To decrease the impact on the environment, factory chimneys must be high enough to allow pollutants to dissipate over a larger a

Komok [63]

Answer:

The probability hat the sample mean height for the 40 chimneys is greater than 102 meters is 0.1469.

Step-by-step explanation:

Let the random variable <em>X</em> be defined as the height of chimneys in factories.

The mean height is, <em>μ</em> = 100 meters.

The standard deviation of heights is, <em>σ</em> = 12 meters.

It is provided that a random sample of <em>n</em> = 40 chimney heights is obtained.

According to the Central Limit Theorem if we have an unknown population with mean <em>μ</em> and standard deviation <em>σ</em> and appropriately huge random samples (<em>n</em> > 30) are selected from the population with replacement, then the distribution of the sample means will be approximately normally distributed.

Then, the mean of the distribution of sample means is given by,

$\mu_{\bar x}=\mu$

And the standard deviation of the distribution of sample means is given by,

$\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}$

Since the sample selected is quite large, i.e. <em>n</em> = 40 > 30, the central limit theorem can be used to approximate the sampling distribution of sample mean heights of chimneys.

$\bar X\sim N(\mu_{\bar x},\ \sigma^{2}_{\bar x})$

Compute the probability hat the sample mean height for the 40 chimneys is greater than 102 meters as follows:

$P(\bar X>102)=P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}})>\frac{102-100}{12/\sqrt{40}})$

$=P(Z>1.05)\\=1-P(Z$

*Use a <em>z</em>-table fr the probability.

Thus, the probability hat the sample mean height for the 40 chimneys is greater than 102 meters is 0.1469.

8 0

3 years ago

Sam found a wrecked car that could she could fix. She bought the car for

katen-ka-za [31]

4,680 I do it like this 50 percent is 3600 then 10 percent is 720 and 5 percent is 360 add then you get 4,680

8 0

3 years ago

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