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3 years ago

What is twenty four over seven as a whole number

Mathematics

2 answers:

babymother [125]3 years ago

8 0

Answer:

It is only 24/7. It cannot be further reduced as a fraction, but it only leads to a decimal.

Step-by-step explanation:

serg [7]3 years ago

5 0

Answer:3 1/7

Step-by-step explanation:

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Equation for, One half the sum of 8 and x

Ahat [919]

Answer:

$\frac{8 + x}{2}$

Step-by-step explanation:

First, we have to write 8 + x, but since it's half of that we write it as a fraction with a 2 on the bottom to halve it.

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3 years ago

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There are 35 people in a room. There are

Degger [83]

Answer:

Male=21 Female=14

Step-by-step explanation:

So the problem would be (f)+(f+7)=35

first you would subtract 7 from 35

Now you have (f)+(f)=28 or 2f=28

Then you divide both sides by two

f=14

and since we know there is 7 more males then the answer is

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

A game decreased in price by 2/3. After the reduction it was priced at £13. What was the original price of the game?

Archy [21]

Answer:

$x = 39$

Step-by-step explanation:

Based on the given conditions, write: $x=\frac{13}{1-\frac{2}{3}}$

Find common denominator and write numerators above common denominator: $x=\frac{\frac{13}{3-2} }{3}$

Calculate the sum or difference: $x=\frac{\frac{13}{1} }{3}$

Divide the fraction by multiplying its reciprocal: $x=13*3$

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2 years ago

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Two identical masses are moving down a slope one masses traveling twice as fast as the other mass how does the kinetic energy of

GaryK [48]

Answer:

One mass's kinetic energy is 4 times the other.

Step-by-step explanation:

The formula for kinetic energy is $KE=\frac{1}{2}mv^2$

Where

KE is the kinetic energy

m is the mass

v is the velocity

Now, let mass of the first be m (second is identical so mass of 2nd is m as well)
Let velocity of the first one be v. Since 2nd one is travelling twice as fast, its velocity will be 2v

KE of 1st mass is:

$\frac{1}{2}mv^2$

KE of 2nd mass is:

$\frac{1}{2}m(2v)^2\\=\frac{1}{2}m(4v^2)\\=\frac{1}{2}mv^2 * 4$

Hence, the kinetic energy of the 2nd mass is 4 times the first.

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3 years ago