Answer:
y=-2
Step-by-step explanation:
Hello : let A(-3,-4) B(6,2)
the slope is : (YB - YA)/(XB -XA)
(2+4)/(6+3) = 6/9 = 2/3
an equation is the line is : y = ax+b a is a slope
y = (2/3)x+b
but this line passes by (6;2)
so : 2 = (2/3)(6)+b
b = -2
the equation is : y = (2/3)x-2
the the Y intercept of this line when : x= 0 so : y = (2/3)(0)-2
y=-2
Sarah has 2 3/4 more meters of rope.
Answer:
Step-by-step explanation:
log8 62 = x1
8^x1= 62
8^2 =64 >62 so <u>x1<2</u>
log7 50=x2
7^x2=50
7^2=49<50 so <u>x2>2</u>
we have, x1<2 and 2<x2
x1<2<x2
x1<x2
log8 62<log7 50
Answer:
D) (0, -3)
Step-by-step explanation:
The solution of two linear equations is the point of intersection of their graphs.
From the graph, the point of intersection of the graphs of the two linear equations is on the y-axis. So, the 
value on the 
axis is always 0. Also, the point is below the x-axis. So, the value of the point will be negative.
From the choices given, only (0,-3) matches the above conditions.
Therefore, the correct choice is D. (0, -3).
From calculus, to determine the maxima or minima of the graph, get the derivative of the equation and equate to zero. So, we derive first the equation of the graph and equate to zero.
C = 0.25x² - 80x + 30000
dC/dx = 0 = 0.5x - 80 + 0
0.5x = 80
x = 80/0.5
x = 160 units
The minimum cost (although not asked) is:
C = 0.25(160)² - 80(160) + 30000
C = $23,600
The answer is 160 units.
