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3 years ago

_____ energy is required to remove an electron from an atom. ((15 POINTS!!))

Chemistry

2 answers:

zloy xaker [14]3 years ago

8 0

It is letter C.
It makes it an ion.<span />

AVprozaik [17]3 years ago

8 0

Hello

The best answer is D.Electron

Have anice day

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Where does baby came from

Oksanka [162]

Answer:

they came from for the dad sperm

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3 years ago

How many g of silver chloride will be produced by reacting 10g of silver nitrate with sodium chloride?

I am Lyosha [343]

Answer:

16.8 g of AgCl are produced

Explanation:

The reactants are: NaCl and AgNO₃

The products are: AgCl, NaNO₃

Balanced equation: NaCl(aq) + AgNO₃(aq) → NaNO₃(aq) + AgCl(s) ↓

We convert the mass of AgNO₃ to moles → 10 g / 85g/mol = 0.117 moles

Ratio is 1:1, therefore 0.117 moles of nitrate will produce 0.117 moles of AgCl.

According to stoichiormetry.

We convert the moles to mass → 0.117 mol . 143.3g /1mol = 16.8 g

7 0

4 years ago

Read 2 more answers

How many moles are present in 100 grams of potassium?

spayn [35]

Answer:

39.0983.

Explanation:

4 0

3 years ago

What is the total charge of the plutonium nucleus? (the neutral plutonium atom has 94 electrons.)?

BabaBlast [244]

94 * 1.602 * 10^-19 =150.588 * 10^-19 C F = kQ(-e)/r^2 we know r = 9.75 angtroms or 9.75 An electric point charge of Q1 = 8.31 nC is placed at the origin of the real axis. Another point charge of Q2 = 2.07 nC is placed at a position of p = 3.06 m on the real axis.Let the sign of Q2 be changed from positive to negative. At which position can the point charge q be placed now so that the net electrostatic force on it is zero?

5 0

4 years ago

A rigid, 2. 50 L bottle contains 0. 458 mol He. The pressure of the gas inside the bottle is 1. 83 atm. If 0. 713 mol Ar is adde

Roman55 [17]

The change in temperature with the addition of Ar to He gas is 68.61 K. The negative change indicates the lowering of the temperature of gas.

<h3>What is an ideal gas equation?</h3>

The pressure of an ideal gas is given by the ideal gas equation as:

PV=nRT

The initial temperature of He gas is given as:

Initial pressure, P=1.83 atm
The initial volume, V=2.50 L
Initial moles of gas, n=0.458 mol
The value of the gas constant, R=0.0821 J/mol.K

Substituting the values for initial temperature, $T_i$ :

$T_i=\rm \dfrac{1.83\;atm\;\times\;2.50\;L}{0.458\;mol\;\times\;0.082\;J/mol.K} \\\textit T_\textit i=122\;K$

The initial temperature of the gas is 122 K.

The addition of 0.713 mol Ar, results in the final values of:

Final pressure, P=2.05 atm
Final volume, V = 2.50 L
Final moles, n=1.171 mol

Substituting the values for final temperature, $T_f$ :

$T_f=\rm \dfrac{2.05\;atm\;\times\;2.50\;L}{1.171\;mol\;\times\;0.082\;J/mol.K} \\\textit T_\textit f=53.3\;K$

The final temperature of the gas is 53.3 K.

The change in temperature ( $\Delta T$ ) is given as:

$\Delta T=T_f-T_i\\\Delta T=53.3-122\;\text K\\\Delta T=-68.61\;\text K$

The change in temperature of the gas is 68.61 K. The negative sign indicates the lowering of temperature with the addition of Ar.

Learn more about ideal gas, here:

brainly.com/question/8711877

4 0

3 years ago