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3 years ago

Why is it necessary to maintain excess bromine in the reaction mixture with trans-cinnamic acid and bromine

Chemistry

1 answer:

DerKrebs [107]3 years ago

4 0

Answer:

It is necessary because Trans-cinnamic is a limiting reagent in the mixture reaction while Bromine is the excess reagent

Explanation:

It is necessary to maintain excess bromine in the reaction mixture because Bromine is the excess reagent in the reaction mixture and if it's quantity is less it would consume the limiting reagent ( Trans-cinnamic ) completely . hence Bromine should maintain excess quantity in the reaction mixture

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If 8.0 g of NH4HS(s) is placed in a sealed vessel with a volume of 1.0 L and heated to 200 ∘C the reaction NH4HS(s) ⇌ NH3(g) + H

PIT_PIT [208]

Answer:

Increasing the volume of the vessel

Explanation:

By the Le Chatelier's principle, if a system in equilibrium suffer a variation that disturbs the equilibriu, the reaction shift in the way to minimize the pertubation and re-establish the equilibrium.

For a variation in pressure, when it increases, the reaction shift for the smallest of gas volume, and if decreases, the reaction will shift for the large gas volume. So, for the reaction given, the products have the large amount of gas, so by decreasing the pressure, more products will be formed, and the amount of NH₄HS will reduce. To decrease the pressure, we can increase the volume of the vessel: for the ideal gas equation (PV= nRT), pressure and volume are indirectly proportional.

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3 years ago

Is it technically correct to call ionic compounds molecules?

stiks02 [169]

Answer:

uh yeah I think so technically

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3 years ago

Read 2 more answers

3. You have 28.5 grams of Carbon. How many atoms is this?

Anton [14]

1 gram of carbon = 12 atoms ..

As per u r question..

28.5 × 12 = 342..

<h2 /><h2>If this answer helps you mark as brainlist..</h2>

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3 years ago

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Aloiza [94]

Answer:

A.It is the same for every sample of a single substance.

Explanation:

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3 years ago

Write the structure of a D-aldohexose that gives a meso compound on treatment with NaBH4 in water.

soldier1979 [14.2K]

Explanation:

Meso compounds are optically inactive stereoisomers. Despite of having chiral carbon, they do not show optical activity because it has a plane of symmetry in its structure itself. It is superposable on its mirror image.

Aldo sugars on reaction which reducing agents such as , NaBH₄ reduces the carbonyl group in the sugar to alcohol and gives corresponding alditol.

The D- aldohexose which on reduction gives a meso alditol are allose and galactose.

The structure is shown in the image below. Thus, in allitol and galactitol formed have internal plane of symmetry which makes the optically inactive.

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3 years ago