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natka813 [3]
4 years ago
11

Calculate the pH of a solution having the following ion concentrations at 298 K. [H+] = 4.6 × 10^-2 M

Chemistry
1 answer:
hodyreva [135]4 years ago
5 0

Answer:

The pH of the solution is 1.34, being an acidic pH.

Explanation:

pH is a measure of acidity or alkalinity that indicates the amount of hydrogen ions present in a solution or substance.   The acronym pH stands for hydrogen potential.

The pH scale ranges from 0 to 14. Values ​​less than 7 indicate the acidity range and those greater than 7 indicate alkalinity or basicity. Value 7 is considered neutral. Mathematically, pH is the negative logarithm of the molar concentration of hydrogen or proton ions (H⁺) or hydronium ions (H₃O⁺).

pH= - log [H⁺] = - log [H₃O⁺]

In this case, [H⁺]= 4.6*10⁻² M. Replacing:

pH= - log 4.6*10⁻²

Solving:

pH= 1.34

<u><em> The pH of the solution is 1.34, being an acidic pH.</em></u>

<u><em></em></u>

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If 1.80 moles of NaCl was dissolved in enough water to make 3.60 L of solution, what is the Molarity?
sweet-ann [11.9K]

Answer:

0.5M

Explanation:

The equation for molarity is:

  • M = \frac{mol}{liters} ; where the "M" stands for molarity, the "mol" stands for moles of solute and the "liters" means the volume in liters of solution.

We are given that there are:

  • 1.80 moles of NaCl (the moles of solute)
  • 3.60 Liters of solution (the volume in liters of solution)

Now we just plug those numbers into the formula and get our answer:

  • M= \frac{1.80mol}{3.60L}= 0.5M

After doing the math and dividing the moles of solute by the liters of solution, we get that the molarity of the solution is 0.5M.

8 0
3 years ago
Rank the following steps involved in preparing a dilute solution from a stock solution in order from first to last.
Serggg [28]

Answer: C - B - A - D

Explanation:

-Obtain a flask that is thoroughly cleaned

-Add the desired amount of stock solution

-Add deionized water until the volume reaches the mark on the flask.

- Cap the flask and invert several times to thoroughly mix the solution.

5 0
3 years ago
Find the % of H in ammonium hydroxide (NH4OH)
nikklg [1K]

Total number of atoms = 7

Total number of H atom = 5

% of H in ammonium hydroxide = 5/7 ×100 = 71.4 %

3 0
3 years ago
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5 0
3 years ago
What is the concentration of nitrate ions in a 0.225 msr(no3)2 solution?
12345 [234]

Answer : The concentration of nitrate ions is 0.450 m.

Solution : Given,

Molarity of Sr(NO_3)_2 = 0.225 m

The balanced ionic equation is,

Sr(NO_3)_2\rightarrow Sr^{+2}+2NO^-_3

From the reaction, we conclude that the 1 mole of Sr(NO_3)_2 produces 2 moles of NO^-_3 ions. That means the concentration of nitrate ions is twice the value of Sr(NO_3)_2.

then, 0.225 m of Sr(NO_3)_2 gives 2 × 0.225 of NO^-_3 ions

Now the concentration of NO^-_3 ions is equal to 0.450 m.


7 0
3 years ago
Read 2 more answers
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