All categories

3 years ago

If Spacecraft X has twice the mass of Spacecraft Y , then what is true about X and Y ?

Physics

1 answer:

Solnce55 [7]3 years ago

6 0

I don't know what you were trying to copy or type in Choice-E .

All three statements are true, so the answer should say "I, II, and III".

You might be interested in

What is the cooling power P? Recall that the rate at which energy is removed, also called the cooling power, was described earli

gayaneshka [121]

Answer:

36.667

Explanation:

(2.2*10^4)/(10*60)

3 0

3 years ago

A 52-kg snow skier is at the top of a 245-m-high hill. After she has gone down a vertical distance of 112 m, what is her total e

Assoli18 [71]

Answer:

a. 125 kJ

Explanation:

Her total energy is the same as the potential energy she had at the top of the hill:

PE = mgh

= (52 kg)(9.8 m/s^2)(245 m) = 124,852 J

≈ 125 kJ . . . . matches choice A

_____

After skiing down 112 m, some of her initial energy is converted to kinetic energy, and some remains as potential energy. We assume the ski slope is essentially frictionless, and air resistance is negligible.

7 0

3 years ago

The momentum of an electron is 1.75 times larger than the value computed non-relativistically. What is the speed of the electron

FrozenT [24]

Answer:

Speed of the electron is 2.46 x 10^8 m/s

Explanation:

momentum of the electron before relativistic effect = $M_{0} V$

where $M_{0}$ is the rest mass of the electron

V is the velocity of the electron.

under relativistic effect, the mass increases.

under relativistic effect, the new mass M will be

M = $M_{0}/ \sqrt{1 - \beta ^{2} }$

where

$\beta = V/c$

c is the speed of light = 3 x 10^8 m/s

V is the speed with which the electron travels.

The new momentum will therefore be

==> $M_{0}V/ \sqrt{1 - \beta ^{2} }$

It is stated that the relativistic momentum is 1.75 times the non-relativistic momentum. Equating, we have

1.75 $M_{0} V$ = $M_{0}V/ \sqrt{1 - \beta ^{2} }$

the equation reduces to

1.75 = $1/ \sqrt{1 - \beta ^{2} }$

square both sides of the equation, we have

3.0625 = 1/ $(1 - \beta ^{2} )$

3.0625 - 3.0625 $\beta ^{2}$ = 1

2.0625 = 3.0625 $\beta ^{2}$

$\beta ^{2}$ = 0.67

β = 0.819

substitute for $\beta = V/c$

V/c = 0.819

V = c x 0.819

V = 3 x 10^8 x 0.819 = 2.46 x 10^8 m/s

6 0

4 years ago

Satellites, A and B, each of mass m, are to be launched into circular orbits about Earth's center. Satellite A is to orbit at an

Volgvan

Answer:

0.63

Explanation:

We are given that

Radius of earth, $R_E=6370 km$

Radius of orbit A, $R_A=7590+6370=13960 km$

Radius of orbit B, $R_B=6370+15800=22170 km$

We have to find the ratio of the potential energy of satellite B to that of satellite A in orbit.

Potential energy of orbit A= $U_A=-\frac{GM}{R_A}=-\frac{GM}{13960}$

Potential energy of orbit B= $U_B=-\frac{GM}{R_B}=-\frac{GM}{22170}$

$\frac{U_B}{U_A}=\frac{13960}{22170}=0.63$

Hence,the ratio of the potential energy of satellite B to that of satellite A in orbit=0.63

8 0

4 years ago

What is the thermal energy of an object?

r-ruslan [8.4K]

I did the quiz, (D) "The total kinetic and potential energies of its particles" is correct.

8 0

3 years ago

Read 2 more answers