Answer:
In odd nuclei, the left out proton or neutron will contribute to the spin of the nucleus.
Explanation:
The meaning of odd nuclei is atomic mass is odd.
A=odd number.
A=Z+n
Here, Z is proton either it will odd or n will odd which is neutron.
Now according to the shell model the left out proton or neutron will contribute to the spin and parity.
For example,
Take the case of isotope of nitrogen-15.
Here Z is 7, and n is 8 will not contribute in spin.
Now, for Z=7.
Here,
and, L=1.
Fort parity,
Put the value of L.
Parity will be -1.
Now, spin will be
.
Answer:
v = K √(E / ρ)
Explanation:
Modulus of elasticity has units of N/m², or kg/m/s².
Density has units of kg/m³.
Velocity has units of m/s.
If we divide modulus of elasticity by density, we can eliminate kg:
E / ρ = [kg/m/s²] / [kg/m³]
E / ρ = [m²/s²]
Taking the square root gets us units of velocity:
√(E / ρ) = [m/s]
Multiply by the constant K:
v = K √(E / ρ)
Answer:
(a) Potential energy of the child is converted into the kinetic energy at the bottom off the slide and a part of which is lost into friction generating heat between the contact surfaces.
(b) 
Explanation:
Given:
- mass of the child,
- height of the slide,
- initial velocity of the child at the slide,
- final velocity of the child at the bottom of slide,
(a)
∴The initial potential energy of the child is converted into the kinetic energy at the bottom off the slide and a part of which is lost into friction generating heat between the contact surfaces.
Initial potential energy:
Kinetic energy at the bottom of the slide:
(b)
Now, the difference in the potential and kinetic energy is the total change in the thermal energy of the slide and the seat of her pants.
This can be given as:
Answer:
0.43
Explanation:
Sum of forces in the y direction:
∑F = ma
N − mg = 0
N = mg
There are friction forces in two directions: centripetal and tangential. The centripetal acceleration is:
ac = v² / r
ac = (35 m/s)² / 564 m
ac = 2.17 m/s²
The total acceleration is:
a = √(ac² + at²)
a = √((2.17 m/s²)² + (3.62 m/s²)²)
a = 4.22 m/s²
Sum of forces:
∑F = ma
Nμ = ma
mgμ = ma
μ = a / g
μ = 4.22 m/s² / 9.8 m/s²
μ = 0.43
Answer:
F= 5195.625 N
Explanation:
To obtain the force needed to hold the child, we need to know the aceleration in which the car is breaking.
Aceleration is equal to velocity divided by the time of breaking
In international system, velocity [m/s] is
v= (62 mi/h)*(1609 m/mi)*(1 h/3600 s)
v= 27.71 m/s
Now, we part the velocity by the time that is 0.08 seconds
a= v/t= (27.71 m/s)/(0.08 s)
a= 346.375 m/
The force in agreement with the Newton's second law is
F=m*a = 15 Kg*346.375 m/
F= 5195.625 N
(Note: 1 N = 1 Kg*m/)
