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Afina-wow [57]
3 years ago
7

A sample of helium (He) occupies 8.0 liters at 1 atm and 20.0◦C. What pressure is necessary to change the volume to 1.0 liters a

t 10.0◦C?
Physics
1 answer:
nevsk [136]3 years ago
7 0

Apply the combined gas law

PV/T = const.

P = pressure, V = volume, T = temperature, PV/T must stay constant.

Initial PVT values:

P = 1atm, V = 8.0L, T = 20.0°C = 293.15K

Final PVT values:

P = ?, V = 1.0L, T = 10.0°C = 283.15K

Set the PV/T expression for the initial and final PVT values equal to each other and solve for the final P:

1(8.0)/293.15 = P(1.0)/283.15

P = 7.7atm

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artcher [175]

The horizontal component of the force is 173.2 N.

The vertical component of the force is 100 N.

The given parameters:

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<h3>Horizontal component of the force</h3>

The horizontal component of the force is calculated as follows;

F_x = Fcos(\theta)\\\\&#10;F_x = 200 \times cos(30)\\\\&#10;F_x = 173.2 \ N

<h3>Vertical component of the force</h3>

The vertical component of the force is calculated as follows;

F_y =F sin(\theta)\\\\&#10;F_y= 200 \times sin(30)\\\\&#10;F_y = 100 \ N

Learn more about components of forces here: brainly.com/question/8106035

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The atlas stone’s is a strong man competition where athletes have to load 5 stones of masses 100kg, 120kg, 140kg, 160kg and 180k
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then the total work that he did is equal to the sum of the work for every stone:

W = (100kg*g*H) + (120kg*g*H) + (140kg*g*H) + (160kg*g*H) + (180kg*g*H)

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and now we can repalce g by 10m/s^2 and H by 125cm

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