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melamori03 [73]
3 years ago
8

If an object is thrown in an upward direction from the top of a building 1.6 x 10^2 ft. high at an initial velocity of 21.82 mi/

h what is its final velocity when it hits the ground? ( disregard wind resistance. Round answer to nearest whole number and do not reflect negative direction in your answer.)
A. 101 ft/s
B. 96 ft/s
C 110 ft/s
Physics
2 answers:
Goshia [24]3 years ago
7 0

If an object is thrown in an upward direction from the top of a building 1.60 x 102 ft. high at an initial velocity of 21.82 mi/h, what is its final velocity when it hits the ground? (Disregard wind resistance. Round answer to nearest whole number and do not reflect negative direction in your answer.)


this question is troubling me i guessed 96 ft/s

can someone help me out and explain it thanks so much!!!!!!



svp [43]3 years ago
4 0

Question: if an object is thrown in an upward direction from the top of a building 1.6 x 10^2 ft. high at an initial velocity of 21.82 mi/h what is its final velocity when it hits the ground? ( disregard wind resistance. Round answer to nearest whole number and do not reflect negative direction in your answer.)

Answer: 110 ft/s

Explanation: Disregard wind resistance round answer to nearest whole number and do not reflect negative direction in your answer is 110

question answered by

(jacemooris04)

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Hunter-Best [27]

Answer:

20 J/g

Explanation:

In this question, we are required to determine the latent heat of vaporization

  • To answer the question, we need to ask ourselves the questions:

What is latent heat of vaporization?

  • It is the amount of heat required to change a substance from its liquid state to gaseous state without change in temperature.
  • It is the amount of heat absorbed by a substance as it boils.

How do we calculate the latent heat of vaporization?

  • Latent heat is calculated by dividing the amount of heat absorbed by the mass of the substance.

In this case;

  • Mass of the substance = 20 g
  • Heat absorbed as the substance boils is 400 J (1000 J - 600 J)

Thus,

Latent heat of vaporization = Quantity of Heat ÷ Mass

                                             = 400 Joules ÷ 20 g

                                             = 20 J/g

Thus, the latent heat of vaporization is 20 J/g

7 0
3 years ago
A large refrigerator (mass 80kg) sits at rest inside a house. The homeowner wants to move the refrigerator across the room, so s
Liono4ka [1.6K]

Answer:

400 N

Explanation:

By the law of friction,

F=\mu R

F is the maximum frictional force, \mu is the coefficient of friction and R is the reaction on the refrigerator. On a horizontal surface, the reaction is equal to the weight of the refrigerator.

R=mg

F=\mu mg

While not moving, the fricition on the refrigerator is static friction. So, \mu=0.65

F=0.65 \times80\times9.8=509.6 \text{ N}

This is the maximum frictional force and is more than the applied horizontal force of 400 N. Frictional force cannot be more than the applied force, else it would actually pull the refrigerator backwards (a strange thing, if it were to happen). It is equal to the extent of the applied force because the applied force is not enough to overcome the maximum.

Hence the frictional force is 400 N.

PS: Note that we do not use the coefficient of kinetic friction because applied force could not overcome the static friction.

6 0
3 years ago
Worth 50 point!!!
stira [4]

Answer:

fact one

Explanation:

fact two is going slower and a longer distance than fact one so fact one will get there first.

hope this helps

4 0
3 years ago
Two 1.0 cm * 2.0 cm rectangular electrodes are 1.0 mm apart. What charge must be placed on each electrode to create a uniform el
kvv77 [185]

Answer:

The number of electrons that must be moved from one electrode to the other to accomplish this is 1.4 X 10⁹ electrons.

Explanation:

<u>Step 1:</u> calculate the charge on each electrode

Given;

Electric field strength = 2.0 X 10⁶ N/C

The distance between the electrode = 1mm = 1 X 10⁻³ m

Electric field strength (E) = Force (F)/Charge (q)

E =\frac{Kq}{r^2}

where;

E is the electric field strength = 2.0 X 10⁶ N/C

K is coulomb's constant = 8.99 X 10⁹ Nm²/C²

r is the distance between the electrodes = 1 X 10⁻³ m

q is the charge in each electrode = ?

q = \frac{Er^2}{K} = \frac{(2X10^6)(1X10^{-3})^2}{8.99 X10 ^9} = 0.2225 X 10⁻⁹ C

The charge on each electrode is 0.2225 X 10⁻⁹ C

<u>Step 2:</u> calculate the number of electrons to be moved from one electrode to the other.

1 electron contains 1.602 X 10⁻¹⁹ C

So, 0.2225 X 10⁻⁹ C will contain how many electrons ?

= (0.2225 X 10⁻⁹)/(1.602 X 10⁻¹⁹)

= 1.4 X 10⁹ electrons

Therefore, the number of electrons that must be moved from one electrode to the other to accomplish this is 1.4 X 10⁹ electrons.

8 0
3 years ago
Um ônibus percorre a distância de 480 km, entre Santos e Curitiba, com velocidade escalar média de 80 km/h. De Curitiba a Floria
Mariulka [41]

Answer:

10 h

Explanation:

velocidade é a taxa de variação da distância no tempo. é a razão entre a distância e o tempo

de Santos e Curitiba:

distância (d) de 480 km, velocidade (s) de 80 km/h

s=\frac{d}{t}\\ t=\frac{d}{s} =\frac{480}{80}=6h

de Curitiba e Florianópolis:

distância (d) de 300 km, velocidade (s) de 75 km/h

s=\frac{d}{t}\\ t=\frac{d}{s} =\frac{300}{75}=4h

tempo médio de ônibus entre Santos e Florianópolis = 6h + 4h = 10h

7 0
3 years ago
Read 2 more answers
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