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taurus [48]
3 years ago
5

Which of the following is a problem that some people blame on technology?

Physics
2 answers:
AnnZ [28]3 years ago
8 0

Answer:

B. widespread pollution

Explanation:

Some people blames technology for widespread pollution.

Pollution is the release of toxic or harmful substances to the earth which is poisonous to human health and harmful to the environment.  These substances when they are released to the environment it causes damage to our environment . Poisonous substance can be solid, liquid or even gaseous.

Advancement in technology like in our transportation system have cause pollution. Previously humans uses animals for transportation. But the advancement in technology have introduce faster transport method like vehicles and train that move on land , planes that moves in air and ships that moves in the sea. Toxic fumes that are harmful to the environment and humans are released because of these advancement in technology. Vehicles releases green house gases like carbon dioxide , Nitrous oxide etc that pollutes the environment.

seropon [69]3 years ago
7 0
The correct answer is B, widespread pollution. If you look closely, you can see that the other answers are not problems at all, but benefits! :)
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Some superconductors are capable of carrying a very large quantity of current. If the measured current is 1.00 ´ 105 A, how many
Zielflug [23.3K]

Answer:

The 6.25 \times 10^{23} electrons are moving through the superconductor per second.

Explanation:

Given :

Current I = 1 \times 10^{5} A

Charge of electron e = 1.6 \times 10^{-19} C

Time t = 1 sec

From the formula of current,

Current is the number of charges flowing per unit time.

   I = \frac{ne}{t}

Where n = number of charges means in our case number of electrons

   n = \frac{It}{e}

   n = \frac{1 \times 10^{5} }{1.6 \times 10^{-19} }

   n = 6.25 \times 10^{23}

Therefore, 6.25 \times 10^{23} electrons are moving through the superconductor per second.

5 0
3 years ago
A softball player moving 3.89 m/s
Ahat [919]

Answer:

0.119 s

Explanation:

Given that

U=3.89\ m/s\\a=-1.44\ m/s^2\\S=4.8\ m

Lets take final speed of the softball after covering 4.8 m = V

We know that

V^2=U^2+2aS\\V^2=3.89^2-2\times 1.44\times 4.8\\V=3.7\ m/s

Also We know that

V=U+at\\

Putting the value of V ,U and a in the previous equation  We get

3.7=3.89-1.44\times t\\t=0.119\ s

Therefore slide time will be 0.119 s

3 0
3 years ago
if a spring has a spring constant of 2 N/m and it is stretched 5 cm, what is the force of the spring?
djyliett [7]

Answer:

0.1 N

Explanation:

Considering the relationship between force,

spring constant and extension as defined by Hook's law

The force F=xk as from Hooke's law where F is the force of the spring, k is spring constant and x is extension or compression. Substituting 2 N/m for k and 5cm which is equivalent to 0.05 m for extention x then the force will be

F=2*0.05=0.1 N

4 0
3 years ago
PLEASE HELP ASAP!! THIS IS DUE IN 15 MUNITES!! Explain what a Precipitate (Not Precipitation) is and tell me if it is a Physical
Amiraneli [1.4K]

Answer:

A precipitate is a solid that separates out of a liquid solution when it is supersaturated (insoluble). This is a chemical change.

Explanation:

Precipitation is when a chemical substance converts into a solid from a solution by converting the substance into an insoluble form or a super-saturated solution. When the reaction occurs in a liquid solution, the solid formed is called the precipitate.

Hope that helps.

3 0
3 years ago
Question 9 In an RC series circuit, ε = 12.0 V, R = 1.07 MΩ, and C = 2.66 µF. (a) Calculate the time constant. (b) Find the maxi
meriva

Answer:

a.) τ = 2.85 s b.) Q = 3.19 * 10^-5 C c.) t = 1.691 s

Explanation:

So we are told that it is a RC circuit. We are told Q = C V [1 - e^(-t/RC)] = 12.0 V, R =  1.07 MΩ and C = 2.66 µF.

a.) The time constant for RC circuit, τ = RC. Substituting our known values we get:

τ = RC where R = (1.07 * 10 ^ 6)Ω and C = (2.66 * 10 ^ -6) F

τ = (1.07 * 10 ^ 6)Ω * (2.66 * 10 ^ -6) F = 2.8462 s ≈ 2.85 s

τ = 2.85 s

b.) The relationship between capacitance, potential, charge is given:

Q = CV[1-e^{-t/RC} ]

The capacitor is fully charge when t approaches infinity, therefore:

Q =  \lim_{t \to \infty} a_n CV[1-e^{-t/RC} ]

When t approaches infinity, the term e becomes very small (e^-∞ = 0), therefore we can simplify the equation and plug in our values

Q = (2.66*10^{-6}) F * (12.0)V *[1 - 0] = 3.192 * 10^{-5}

Q = 3.19 * 10^-5 C

c.) Using the same equation as before, we can substitute Q in and solve for Q:

(14.3 * 10 ^ 6) C = (2.66*10^{-6})F *(12.0)V*[1-e^{-t/(2.85s)}]\\0.552 = e^{-t/(2.85s)}\\t = -1 * 2.85 * ln(0.552) \\t = 1.69120678 s

t = 1.691 s

Hope this helps! I'm not sure what the units you want, so convert to the desired units.

6 0
3 years ago
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