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tensa zangetsu [6.8K]
3 years ago
12

How can wind be used as a source of power?

Chemistry
2 answers:
Andre45 [30]3 years ago
7 0
The motion of the wind can turn wind turbines
kicyunya [14]3 years ago
5 0

Answer:

Drilling in the earth can provide new sources of wind

Explanation:

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How many moles are in 14.35 x 1022 molecules of H3PO4?
Irina18 [472]

Answer:

0.24mole

Explanation:

Given parameters:

Number of molecules  = 14.35 x 10²² molecules;

       Unknown = number of moles of H₃PO₄

 A mole of a substance is the quantity of matter that contains the avogadro's number of particles.

 This number is given as 6.02 x 10²³ particles. The particles can be atoms, molecules, protons, electrons e.t.c

          6.02 x 10²³ molecules is contained in 1 mole of any substance

          14.35 x 10²² molecules will contain:  \frac{1.435 x 10^{23} }{6.02 x 10^{23} }   = 0.24mole

7 0
3 years ago
You look for shells when you visit the beach. However, if you're hiking in the mountains and you find shells by accident, you kn
Lubov Fominskaja [6]

Answer:ThE aNsWeR iS B

Explanation: The earth was one a big ocean but than volcanoes explode and that created land :)

6 0
3 years ago
Read 2 more answers
A sample of gas A has a molar mass of 4 grams while a sample of gas B has a molar mass of 16 grams. Which statement holds true?
jeka94

I believe the closest possible answer to this question are:Gas A effuses faster than gas B.The molar mass is directly proportional to the rate of effusion.Thank you for your question. Please don't hesitate to ask in Brainly your queries
4 0
4 years ago
Read 2 more answers
650.0 mL of a gas is under a pressure of 840.0 torr. What would the volume of
zheka24 [161]

Answer:

Explanation:using the ideal gas formula, calculate the volume of 1.5omoles of a gas at 115kPA and a temperature of 298k?

6 0
2 years ago
1.12g H2 is allowed to react with 9.60 g N2, producing 1.23 g NH3.
andriy [413]

Answer:

A. m_{NH_3}^{theo} =1.50gNH_3

B. Y=82.2\%

Explanation:

Hello!

In this case, since the undergoing chemical reaction between nitrogen and hydrogen is:

N_2+3H_2\rightarrow 2NH_3

Thus we proceed as follows:

A. Here, we first need to compute the moles of ammonia yielded by each reactant, in order to identify the limiting one:

n_{NH_3}^{by \ H_2}=1.12gH_2*\frac{1molH_2}{2.02gH_2}*\frac{2molNH_3}{3molH_2}=0.370molNH_3\\\\  n_{NH_3}^{by \ N_2}=1.23gN_2*\frac{1molN_2}{28.02gN_2}*\frac{2molNH_3}{1molN_2}=0.0878molNH_3

Thus, since nitrogen yields the fewest moles of ammonia, we realize it is the limiting reactant, so the theoretical yield, in grams, of ammonia is:

m_{NH_3}^{theo}=0.0878mol*\frac{17.04gNH_3}{1molNH_3} =1.50gNH_3

B. Finally, since the actual yield of ammonia is 1.23, the percent yield turns out:

Y=\frac{1.23gNH_3}{1.50gNH_3} *100\%\\\\Y=82.2\%

Best regards!

5 0
3 years ago
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