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zhannawk [14.2K]
3 years ago
12

2 Zn + O2 → 2 ZnO

Chemistry
1 answer:
meriva3 years ago
3 0

Answer:

we need 6.0 moles of zinc (Zn)

Explanation:

Step 1: Data given

Number of moles ZnO produced = 6.0 moles

Step 2: The balanced equation

2 Zn + O2 → 2 ZnO

For 2 moles Zinc we need 1 mol Oxygen to produce 2 moles Zinc oxide

Step 3: Calculate moles zinc

For 2 moles Zn we need 1 mol O2 to produce 2 moles ZnO

For 6.0 moles 2nO produced, we need 6.0 moles of zinc (Zn) and 3.0 moles of O2 to react.

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A diffusion coefficient KG was determined for the diffusion of a gas A through a stagnant film B [KG = 0.88 mol//h-ft2-atm].
Angelina_Jolie [31]

Explanation:

Transfer of mass A into stagnant film B depends on the availability of driving force.

Whereas driving force is the pressure difference at the surface of A and the bulk.

As,       N_{A} \propto (P_{A1} - P_{A2})

           N_{A} = K_{G} \times (P_{A1} - P_{A2})

Therefore, putting the given values into the above formula as follows.

         N_{A} = K_{G} \times (P_{A1} - P_{A2})

                     = 0.88 \times (0.2 atm - 0.05 atm)

                     = 0.132 mol/h.ft^{2}

Thus, we can conclude that the flux of A from a surface into a mixture of A and B is 0.132 mol/h.ft^{2}

4 0
4 years ago
What is the ROUNDED atomic number for this elements?
denis-greek [22]
Sodium/Atomic number

11

Gold/Atomic number

79
Potassium/Atomic number

19

Silicon/Atomic number

14




8 0
3 years ago
Pls help me in this:(​
antiseptic1488 [7]

Answer:

a) 26.98

b) 3

c) 3* 1.01 = 3.03

d) 3 *16 = 48

e) 26.98 + 3.03 + 48 = 78.01

f) 6.023 * 10²³

3 0
3 years ago
In the following equation, which element has been reduced?
Mila [183]
The answer is A. you sre correct!
4 0
3 years ago
A 10.0 ml portion of 0.010 m hcl is diluted by adding it to100.0 ml of water. what is the ph of the solution
Volgvan

From the calculation, the pH of the solution after dilution is 3.

<h3>What is the pH?</h3>

The pH is the hydrogen ion concentration of the solution. Now we know that;

C1 =  0.010 m

V1 = 10.0 ml

V2 = 10.0 ml + 100.0 ml = 110 ml

C2 = ?

C1V1 = C2V2

C2 = C1V1 /V2

C2 =  0.010 m  * 10.0 ml / 110 ml

C2 = 0.00091 M

pH = -log[0.00091 M]

pH = 3

Learn more about pH:brainly.com/question/15289741

#SPJ1

4 0
2 years ago
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