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zhannawk [14.2K]
4 years ago
12

2 Zn + O2 → 2 ZnO

Chemistry
1 answer:
meriva4 years ago
3 0

Answer:

we need 6.0 moles of zinc (Zn)

Explanation:

Step 1: Data given

Number of moles ZnO produced = 6.0 moles

Step 2: The balanced equation

2 Zn + O2 → 2 ZnO

For 2 moles Zinc we need 1 mol Oxygen to produce 2 moles Zinc oxide

Step 3: Calculate moles zinc

For 2 moles Zn we need 1 mol O2 to produce 2 moles ZnO

For 6.0 moles 2nO produced, we need 6.0 moles of zinc (Zn) and 3.0 moles of O2 to react.

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To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}    .....(1)

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Putting values in equation 1, we get:

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By Stoichiometry of the reaction:

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Putting values in equation 1, we get:

0.085M=\frac{\text{Moles of magnesium nitrate}}{1.5L}\\\\\text{Moles of magnesium nitrate}=(0.085mol/L\times 1.5L)=0.1275mol

1 mole of magnesium nitrate contains 1 mole of magnesium ions and 2 moles of nitrate ions

Moles of magnesium ions = 0.1275 moles

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3Mg^{2+}+2PO_4^{3-}\rightarrow Mg_3(PO_4)_2

By Stoichiometry of the reaction:

3 moles of magnesium ions reacts with 2 moles of phosphate ions

So, 0.1275 moles of magnesium ions will react with = \frac{2}{3}\times 0.1275=0.085mol of phosphate ions

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To calculate the number of moles, we use the equation:

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Putting values in above equation, we get:

0.135mol=\frac{\text{Mass of sodium phosphate}}{164g/mol}\\\\\text{Mass of sodium phosphate}=(0.135mol\times 164g/mol)=22.14g

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