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IceJOKER [234]
3 years ago
8

According to chebyshev's theorem at least what percent of any set of observations will be within 1.8 standard deviations of the

mean
Mathematics
1 answer:
SOVA2 [1]3 years ago
8 0
Chebyshev's theorem states that for a large class of distributions, no more than 1/k² of the distribution will be k standard deviations away from the mean.

This means that 1 - 1/k² of the distribution will be within k standard deviations from the mean.

Because k = 1.8, the amount of the distribution that is within 1.8 standard deviations from the mean is
1 - 1/1.8² = 0.6914 = 69.14%

Answer:  69.1%

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nikklg [1K]

Answer:

yes

Step-by-step explanation:

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Simplify. I'm don't know how to type it so I am going to take a picture.​
Vesnalui [34]

Answer:2/1

Step-by-step explanation:

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3 years ago
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6 cm<br> 16 cm<br> What is the volume of the cylinder?
jenyasd209 [6]

V = 576 pi cm^3

Step-by-step explanation:

The volume of a cylinder is given by

V = pi r^2 h  where r is the radius and h is the height

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5 0
3 years ago
A set X consists of all real numbers greater than or equal to 1. Use set-builder notation to define X.
vitfil [10]

Theory:

The standard form of set-builder notation is <span>
 
{ x | “x satisfies a condition” } </span>

This set-builder notation can be read as “the set of all x such that x (satisfies the condition)”.

For example, { x | x > 0 }  is equivalent to “the set of all x such that x is greater than 0”.

 

Solution:

In the problem, there are 2 conditions that must be satisfied:

<span>1st: x must be a real number</span>

In the notation, this is written as “x ε R”. Where ε means that x is “a member of” and R means “Real number”

 

<span>2nd: x is greater than or equal to 1</span>

This is written as “x ≥ 1”

 

Answer:

Combining the 2 conditions into the set-builder notation:

<span>X = { x | x ε R and x ≥ 1 } </span>
8 0
3 years ago
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Last week’s and this week’s low temperatures are shown in the table below. Low Temperatures for 5 Days This Week and Last Week L
STatiana [176]

Question:

Temperatures for 5 Days This Week and Last Week

Low Temperatures This Week (Degrees Fahrenheit) 4 10 6 9 6 Low Temperatures Last Week (Degrees Fahrenheit) 13 9 5 8 5 Which measures of center or variability are greater than 5 degrees? Select three choices.

a) the mean of this week’s temperatures

b) the mean of last week’s temperatures

c) the range of this week’s temperatures

d)the mean absolute deviation of this week’s temperatures

e) the mean absolute deviation of last week’s temperatures

Answer:

a) the mean of this week’s temperatures

b) the mean of last week’s temperatures

c) the range of this week’s temperatures

Step-by-step explanation:

I would be verifying the options a, b, and c in my answer above through calculations which are shown below.

We were given the following data:

Low Temperatures This Week (Degrees Fahrenheit)

4, 10, 6, 9, 6

Low Temperatures Last Week (Degrees Fahrenheit)

13, 9, 5, 8, 5

We are to find which measures of center or variability are greater than 5 degrees.

Option a

The mean of this week’s temperatures

(4+ 10+ 6+9+ 6) °F ÷ 5 = 35 °F ÷5 = 7°F

Option a is correct because it measures of center or variability which is 7 °F is higher than 5°F

Option b

The mean of last week’s temperatures

(13+ 9 + 5 + 8 + 5) °F = 40°F ÷ 5 = 8°F

Option b is correct , because its measure of variability which is 8°F is greater than 5°F.

Option c

the range of this week’s temperatures

This week's temperature is given as

(4, 10, 6, 9, 6) °F

Range is defined as the difference between the highest number and the lowest number

Range of this week's temperature = (10 - 4) °F = 6°F

Hence Option c is correct because it measures of center or variability which is 6°F is greater than 5°F

From the above calculations we can accurately confirm that options a, b, and c are correct because the measures of their center or variability is greater than 5°F

3 0
3 years ago
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