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worty [1.4K]
3 years ago
5

Rewrite this formula to solve for GGi: DX=fL/GGi

Physics
1 answer:
sashaice [31]3 years ago
3 0
Comment if you need clarification!

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Light with a wavelength of 400 nm strikes the surface of cesium in a photocell, and the maximum kinetic energy of the electrons
Firdavs [7]

Answer:

The longest wavelength of light that is capable of ejecting electrons from that metal is 1292 nm.

Explanation:

Given that,

Wavelength = 400 nm

Energy E=1.54\times10^{-19}\ J

We need to calculate the longest wavelength of light that is capable of ejecting electrons from that metal

Using formula of energy

E = \dfrac{hc}{\lambda}

\lambda=\dfrac{hc}{E}

Put the value into the formula

\lambda=\dfrac{6.63\times10^{-34}\times3\times10^{8}}{1.54\times10^{-19}}

\lambda=1292\times10^{-9}\ m

\lambda=1292\ nm

Hence, The longest wavelength of light that is capable of ejecting electrons from that metal is 1292 nm.

8 0
3 years ago
15 points for 2 questions
Elden [556K]
I believe the answer would be c because i think that you multiply the 2
8 0
3 years ago
Read 2 more answers
What do the arrows in food chains represent
OLga [1]
To represent in order how the animals

6 0
3 years ago
Read 2 more answers
Applying Kirchhoff’s Junction Rule, what happens to the power source and current when the parallel circuit has two branches, eac
slamgirl [31]

The power source voltage remains the same in a  parallel circuit,

And we'll have equal current in both lines

<h3>Kirchhoff's junction rule</h3>

Generally, Kirchhoff's junction rule states that when there is current flow at any junction of a circuit, the total sum of this current rushing into the junction amount to the same amount of current out of the Node.

Therefore, when the parallel circuit has two branches

i=i1+12

Since we have an equal resistor therefore we'll have equal current in both lines i.e i1=i2

And Voltage remains the same in a  parallel circuit

More on Voltage

brainly.com/question/14883923

7 0
2 years ago
How much heat energy must be added to 52kg Of water at 68°F to raise the temperature to 212°F? The specific heat capacity for wa
Anna [14]

Answer:

The amount of energy added to rise the temperature Q = 17413.76 KJ

Explanation:

Mass of water = 52 kg

Initial temperature T_{1} = 68 °F = 20° c

Final temperature T_{2} = 212 °F = 100° c

Specific heat of water  C = 4.186 \frac{KJ}{kg c}

Now heat transfer Q = m × C × ( T_{2}  - T_{1} )

⇒ Q = 52 × 4.186 × ( 100 - 20 )

⇒ Q = 17413.76 KJ

This is the amount of energy added to rise the temperature.

4 0
3 years ago
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