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Mandarinka [93]
3 years ago
15

What is the unit of velocity ratio and mechanical advantage and why​

Physics
1 answer:
alexandr402 [8]3 years ago
8 0
Both don’t have units beacuse they are ratios
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An object starts at Xi = -4m with an initial velocity of 4m/s. It experiences an acceleration of -2 m/s^2 for 2 seconds, followe
GalinKa [24]

Answer:

a) 0 m/s

b) - 24 m/s

c)  - 68 m

Explanation:

Given:

Initial distance = - 4 m

Initial velocity, u = 4 m/s

1) acceleration, a = - 2 m/s² for time, t = 2 seconds

thus,

velocity after 2 seconds will be

from Newton's equation of motion

v = u + at

v = 4 + (-2) × 2

v = 0 m/s

2) Velocity after 2 second is the initial velocity for this case

given acceleration = - 6 m/s² for 4 seconds

thus,

final velocity, v = 0 + ( - 6 ) × 4 = - 24 m/s

here the negative sign depicts the velocity in opposite direction to the initial direction of motion

thus, velocity after 6 seconds = - 24 m/s

3) Now,

Total displacement in 6 seconds

= Displacement in 2 seconds + Displacement in 4 seconds

From Newton's equation of motion

s=ut+\frac{1}{2}at^2

where,  

s is the distance

u is the initial speed  

a is the acceleration

t is the time

thus,

= 0\times2+\frac{1}{2}\times(-2)\times2^2  + 0\times4+\frac{1}{2}\times-6\times4^2

= - 16 - 48

= - 64 m

Hence, the final displacement = - 64 - 4 = - 68 m

5 0
3 years ago
Two horizontal pipes have the same diameter, but pipe B is twice as long as pipe A. Water undergoes viscous flow in both pipes,
zheka24 [161]

Answer:

c) 2Q

Explanation:

From the given information:

The pressure inside a pipe can be expressed by using the formula:

\Delta P = \dfrac{128 \mu L Q}{\pi D^4}

Since the diameter in both pipes is the same, we can say:

D = D_A = D_B

where;

length of the first pipe A L_A = L and the length of the second pipe B L_B = 2L

Since the difference in pressure is equivalent in both pipes:

Then:

\dfrac{128 \mu L_1Q_1}{\pi D_1^4} = \dfrac{128 \mu L_2Q_2}{\pi D_2^4}

\dfrac{ L_1Q_1}{D_1^4} = \dfrac{ L_2Q_2}{D_2^4}

\dfrac{ LQ_1}{D^4} = \dfrac{ 2LQ}{D^4}

\mathbf{Q_1 = 2Q}

6 0
3 years ago
A 5000-kg freight car crashes into a 10,000-kg freight car at rest. They couple upon collision and move with a speed of 2 m/s. W
nirvana33 [79]

Answer:

6 m/s

Explanation:

mass of moving car m1=5000 kg

initial velocity of moving car vi1=?

mass of car at rest = m2=10000 kg

initial velocity of car at rest = vi2=0

final velcoities of both cars after collision = vf1=vf2= 2m/s

using conservation of momentum rule

m1vi1+m2vi2=m1vf1+m2vf2

putting values

==> 5000 × vi1 + 1000 × 0 = 5000 × 2 + 10000 × 2

==> 5000 ×vi1 = 2 × 15000

==> vi1 = 2 × 15000 ÷ 5000

==> vi1= 2×3=6 m/s

8 0
3 years ago
Describe 4 common workplace practices that are risk factors for injury
Aleonysh [2.5K]
High task repitition, forceful exertions, repetitive or sustained awkward posture
7 0
3 years ago
What does the SLOPE of a Velocity-Time graph represent? *<br> 1 point
lyudmila [28]

Acceleration

Explanation:

  • In the Velocity-Time graph Velocity is taken in Y-Axis and plotted against Time in X-Axis.
  • The unit of velocity is mentioned in m/s and unit of time is mentioned in seconds.
  • Here we can analyze the instantaneous acceleration and displacement covered.
  • From the slope we can get the body accelerated.
  • From the area under the graph we can get the displacement traveled.
  • We can calculate both average and Instantaneous acceleration from the slope of this graph.

6 0
3 years ago
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