Answer:
IN MOTION
Explanation:
An apparent change in the frequency of waves, as of sound or light, occurring when the source and observer are in motion relative to each other, with the frequency increasing when the source and observer approach each other and decreasing when they move apart.
Explanation:
1. The Centauri star system consists of 3 stars and is about 4.37 light-years away from Earth. (A light-year is the distance that light travels in a year.)
2. We see the visible spectrum which consists of colors red, orange, yellow, green, blue, indigo, and violet. (The visible spectrum is the range of light that our eyes can detect.)
3. Because air has a lower index of refraction than water, the light beams making up the image of the fish I see bends as it leaves the water and enters the air. (Index of refraction determines how light bends when moving from one medium into another.)
4. When I look at my reflection in the mirror, the light reflects off the mirror at an equal but opposite angle as it hits the mirror.
5. When looking into a concave mirror the center is further away from you than the outside edges. (Concave mirrors cave in.)
6. Forklift drivers are careful to look in the convex mirrors placed at blind intersections in the warehouse.
7. is transparent and the light goes through without distortion.
8. The electromagnetic spectrum refers to any or all of the possible wavelengths of "light", both the visible light and invisible light.
9. The transmission of light through a medium means it goes through it.
10. The absorption of light by a medium means it is absorbed by it.
Complete question is;
a. Two equal sized and shaped spheres are dropped from a tall building. Sphere 1 is hollow and has a mass of 1.0 kg. Sphere 2 is filled with lead and has a mass of 9.0 kg. If the terminal speed of Sphere 1 is 6.0 m/s, the terminal speed of Sphere 2 will be?
b. The cross sectional area of Sphere 2 is increased to 3 times the cross sectional area of Sphere 1. The masses remain 1.0 kg and 9.0 kg, The terminal speed (in m/s) of Sphere 2 will now be
Answer:
A) V_t = 18 m/s
B) V_t = 10.39 m/s
Explanation:
Formula for terminal speed is given by;
V_t = √(2mg/(DρA))
Where;
m is mass
g is acceleration due to gravity
D is drag coefficient
ρ is density
A is Area of object
A) Now, for sphere 1,we have;
m = 1 kg
V_t = 6 m/s
g = 9.81 m/s²
Now, making D the subject, we have;
D = 2mg/((V_t)²ρA))
D = (2 × 1 × 9.81)/(6² × ρA)
D = 0.545/(ρA)
For sphere 2, we have mass = 9 kg
Thus;
V_t = √[2 × 9 × 9.81/(0.545/(ρA) × ρA))]
V_t = 18 m/s
B) We are told that The cross sectional area of Sphere 2 is increased to 3 times the cross sectional area of Sphere 1.
Thus;
Area of sphere 2 = 3A
Thus;
V_t = √[2 × 9 × 9.81/(0.545/(ρA) × ρ × 3A))]
V_t = 10.39 m/s
