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4 years ago

Describe what long sight is and how it is corrected with a lens

Physics

1 answer:

o-na [289]4 years ago

7 0

If long sight means farsighted, then here's your answer:

Farsightedness is when the lens has difficulty focusing on nearby objects. Sufferers must squint to see the nearby objects. Reading, writing, and drawing for longer periods of time can cause eyestrain and headache.

Being farsighted can be corrected with prescription glasses or contact lenses or surgery.

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A 126- kg astronaut (including space suit) acquires a speed of 2.70 m/s by pushing off with her legs from a 1800-kg space capsul

jeka94

The change in the speed of the space capsule will be -0.189 m/s.

The average force exerted by each on the other will be 567 N.

The kinetic energy of each after the push for the astronaut and the capsule are 459.27 J and 32.14 J.

<h3>Given:</h3>

Mass of the astronaut, $m_a$ = 126 kg

Speed he acquires, $v_{a}$ = 2.70 m/s

Mass of the space capsule, $m_{c}$ = 1800kg

The initial momentum of the astronaut-capsule system is zero due to rest.

$P_f = m_av_a + m_cv_c$

$P_I$ = 0

$m_av_a + m_cv_c = 0$

$v_c =\frac{- m_a v_a}{m_c}}\\\\$

$= \frac{126* 2.70}{1800}$

$= - 0.189$ m/s

Therefore,

According, to the impulse-momentum theorem;

FΔt = ΔP

ΔP = m Δv

ΔP = 126×2.70

= 340.2 kgm/sec

t is time interval = 0.600s

F = ΔP/Δt

F = 340.2/0.600

= 567 N

Therefore, the average force exerted by each on the other will be 567 N.

The Kinetic Energy of the astronaut;

K.E = $\frac{1}{2} m v^2$

$= \frac{1}{2}$ × 126 × $(2.70) ^2$

= 459.27 J

The Kinetic Energy of the capsule;

K.E = $\frac{1}{2} m v^2$

= $\frac{1}{2}$ ×1800× $(0.189) ^2$

= 32.14 J

Therefore, the kinetic energy of each after the push for the astronaut and the capsule are 459.27 J and 32.14 J.

Learn more about kinetic energy here:

brainly.com/question/26520543

#SPJ1

3 0

2 years ago

What happens when you "crack/pop your knuckles?

Art [367]

It could result in it not being good for your joints, as well as in the long run but shouldn't cause problems when your a child. I hope this helps your question!

6 0

3 years ago

An object of mass 100kg is raised 2m above the ground using an Inclined Plane of length 10m calculate the effort parallel to inc

MArishka [77]

Answer:

Slope = 2 m / 10 m = 1/5

For every 5 m of effort the object will be raised 1 m

W = work done on object = M g h increase in PE of object

E S = W where E is effort and S the distance thru which the effort acts

E S = M g H

E = 100 kg * 9.8 m/s^2 * 2 m / 10 m = 196 kg m / s^2 = 196 N

Check: total work = 2 * 9.8 * 100 = 1960 J

Force Needed = 1960 J / 2 m = 980 Newtons

Mechanical advantage = 980 / 196 = 5 as one would expect since the object is raised 1 m for every 5 m of force input

8 0

2 years ago

How is it possible to fill medicine in a syringe?

Hunter-Best [27]

Links do not help buddy stop doing it on everything !!!!!!

5 0

3 years ago

Micah knows that a car had a change in velocity of 15 m/s.To determine acceleration ,Micah also needs the blank of the total tri

Fittoniya [83]

Answer: To determine acceleration ,Micah also needs the Time of the total trip in seconds.

Explanation:

Acceleration can be defined as rate of change of velocity.

$a = \frac{dv}{dt}$

for calculating acceleration, initial and final velocity are required in meter per second and the total time of the trip in seconds. Then acceleration is measured in meter per second square.

Thus, Micah knows that a car had a change in velocity of 15 m/s.To determine acceleration ,Micah also needs the <u>Time</u> of the total trip in seconds.

7 0

4 years ago

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