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3 years ago

During a test, what can a student use to identify what type and how many atoms are in a chemical compound?

Physics

2 answers:

taurus [48]3 years ago

8 0

Answer:

the answer is actually chemical names

Explanation:

I took the test :p

11111nata11111 [884]3 years ago

5 0

Answer:

C- ths answer is the letter C

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Use the inverse square law for light to answer each of the following questions. Part A Suppose a star has the same luminosity as

Alinara [238K]

Answer

The apparent brightness by inverse square law is $3.25*10^-^9watt/m^2$

Explanation:

b = L / ( 4 pi d^2 )

b = apparent brightness of the star (in watts/meter2)

L = luminosity of the star (in watts)

d = distance to the star (in meter)

pi = approximately 3.14159265

$Given\\d=10 light years=9.461*10^1^6\\L=3.8*10^2^6watts$

put all values in formula

$b=(3.8*10^2^6)/4*3.14*(9.641*10^1^6)^2$

$b=3.25*10^-^9watts/m^2$

3 0

3 years ago

The parallel plates in a capacitor, with a plate area of 8.50 cm2 and an air-filled separation of 3.00 mm, are charged by a 6.00

Vera_Pavlovna [14]

Answer:

(a). The charge is $1.5045\times10^{-11}\ C$

(b). The initial stored energy is $4.5135\times10^{-11}\ J$

(c). The final stored energy is $12.036\times10^{-11}\ J$

(d). The work required to separate the plates is $7.5225\times10^{-11}\ J$

Explanation:

Given that,

Area = 8.50 cm²

Distance = 3.00 mm

Potential = 6.00 V

Distance without discharge = 8.00 mm

(a). We need to calculate the capacitance

Using formula of capacitance

$C_{1}=\dfrac{\epsilon_{0}A}{d}$

Put the value into the formula

$C_{1}=\dfrac{8.85\times10^{-12}\times8.5\times10^{-4}}{3.00\times10^{-3}}$

$C_{1}=2.5075\times10^{-12}\ F$

We need to calculate the charge

Using formula of charge

$Q=CV$

Put the value into the formula

$Q=2.5075\times10^{-12}\times6.00$

$Q=1.5045\times10^{-11}\ C$

(b). We need to calculate the initial stored energy

Using formula of initial energy

$E_{i}=\dfrac{1}{2}\times CV^2$

$E_{i}=\dfrac{1}{2}\times2.5075\times10^{-12}\times36$

$E_{i}=4.5135\times10^{-11}\ J$

(c). We need to calculate the capacitance

Using formula of capacitance

$C_{2}=\dfrac{\epsilon_{0}A}{d}$

Put the value into the formula

$C_{2}=\dfrac{8.85\times10^{-12}\times8.5\times10^{-4}}{2\times8.00\times10^{-3}}$

$C_{2}=9.403\times10^{-13}\ F$

We need to calculate the final stored energy

Using formula of initial energy

$E_{f}=\dfrac{1}{2}\times \dfrac{Q^2}{C}$

$E_{f}=\dfrac{1}{2}\times\dfrac{(1.5045\times10^{-11})^2}{9.403\times10^{-13}}$

$E_{f}=12.036\times10^{-11}\ J$

(d). We need to calculate the work done

Using formula of work done

$W=E_{f}-E_{i}$

Put the value in the formula

$W=12.036\times10^{-11}-4.5135\times10^{-11}$

$W=7.5225\times10^{-11}\ J$

Hence, (a). The charge is $1.5045\times10^{-11}\ C$

(b). The initial stored energy is $4.5135\times10^{-11}\ J$

(c). The final stored energy is $12.036\times10^{-11}\ J$

(d). The work required to separate the plates is $7.5225\times10^{-11}\ J$

5 0

4 years ago

A penny is kicked horizontally off the roof of a 10-story building (33.3 m high) and lands 52 m away on the ground. A) what is t

yanalaym [24]

A) The penny was kicked horizontally off the building. By this very statement, the penny had 0 initial vertical velocity.

B) Apply the following kinematics equation to the penny's vertical motion:

D = Vt + 0.5At²

D = vertical distance traveled, t = time, V = initial vertical velocity, A = vertical acceleration

Given values:

D = 33.3m, V = 0m/s, A = 9.81m/s²

Plug in and solve for t:

33.3 = 4.905t²

t = 2.61s

C) The penny fell for 2.61 seconds, therefore it moved horizontally for 2.61 seconds.

v = x/t

v = horizontal velocity, x = horizontal distance traveled, t = time

Given values:

x = 52m, t = 2.61s

Plug in and solve for v:

v = 52/2.61

v = 19.9m/s

D) Let's calculate the penny's vertical speed right before it hits the ground:

v = at

v = final vertical speed, a = vertical acceleration, t = time

Given values:

a = 9.81m/s², t = 2.61s

Plug in and solve for v:

v = 9.81(2.61)

v = 25.6m/s

Use the Pythagorean theorem to find the final speed:

V = √(Vx²+Vy²)

V = final speed, Vx = final horizontal speed, Vy = final vertical speed

Given values:

Vx = 19.9m/s, Vy = 25.6m/s

Plug in and solve for V:

V = √(19.9²+25.6²)

V = 32.4m/s

5 0

3 years ago

A trolley of mass 4 kg moves with a velocity of 0.5 meter per second It colides with a stationary trolley of mass 3 kg. If the t

Luda [366]

Answer:

Approximately $0.29\; {\rm m \cdot s^{-1}}$ .

Explanation:

Make use of the fact that total momentum is conserved in collisions.

The momentum of an object of mass $m$ and velocity $v$ is $p = m\, v$ .

The momentum of the two trolleys before the collision would be:

$4\; {\rm kg} \times 0.5\; {\rm m \cdot s^{-1}} = 2\; {\rm kg \cdot m \cdot s^{-1}}$ .
$3\; {\rm kg} \times 0\; {\rm m\cdot s^{-1}} = 0\; {\rm kg \cdot m \cdot s^{-1}}$ .

Thus, the total momentum of the two trolleys right before the collision would be $2\; {\rm kg \cdot m \cdot s^{-1}}$ .

Since the two trolleys are stuck to one another after the collision, they could modelled as one big trolley of mass $m = 3\; {\rm kg} + 4\; {\rm kg} = 7\; {\rm kg}$ .

The momentum of the two trolleys, combined, is conserved during the collision. Thus, the total momentum of the new trolley of mass $m = 7\; {\rm kg}$ would continue to be $v = 2\; {\rm kg \cdot m \cdot s^{-1}}$ shortly after the collision.

Rearrange the equation $p = m\, v$ to find the velocity of the two trolleys combined:

$\begin{aligned}v &= \frac{p}{m} \\ &= \frac{2\; {\rm kg \cdot m \cdot s^{-1}}}{7\; {\rm kg}} \\ &\approx 0.29\; {\rm m \cdot s^{-1}}\end{aligned}$ .

6 0

2 years ago

In the Earth's mantle, heat is transferred in large convection currents. Within these currents,

liq [111]

A.cooler and hotter rock rise but do not sink.

B.hotter and cooler rock sink but do not rise.

C.hotter rock rises and cooler rock sinks.

D.cooler rock rises and hotter rock sinks.

hotter rock rises and cooler rock sinks.

Answer: Option C.

<u>Explanation:</u>

The process that happens inside the surface of earth makes the rocks inside the surface to either expand or shrink in size because of the presence of heat inside the surface.

Heat rises and as the warmer rock gets further away from the super heated center of the Earth it begins to cool off and starts to sink back toward the super heated center of the Earth where it is reheated and the whole process starts over again. That is what a convection current is.

8 0

3 years ago

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