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pashok25 [27]
4 years ago
10

-f=-100 solve for f f= wold the answer be 1

Mathematics
1 answer:
marshall27 [118]4 years ago
6 0
1 is incorrect. to solve for f, you have to get it alone, and right now you have a negative sign in your way.

you can eliminate the negative by dividing both sides by -1:

-f = -100

divide by -1 to cancel out the - in front of f

f = 100
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PLEASE HELP!!!!
Lunna [17]

NOTES:

Given a quadratic function in standard format (y = ax² + bx + c), the direction of the parabola is as follows:

  • if "a" is positive, then opens UP
  • if "a" is negative, then opens DOWN

Given a quadratic function in standard format (y = ax² + bx + c), the vertex can be found as follows:

  • the Axis Of Symmetry (x-value) is: x = \frac{-b}{2a}  
  • y-value is found by plugging in the AOS for "x" in the equation

****************************************************************************************

1) y = x² + 11x + 24

  • a = +1 so the parabola opens UP
  • x = \frac{-b}{2a} = \frac{-11}{2(1)}  = -\frac{11}{2}
  • y = (-\frac{11}{2})^{2} + 11(-\frac{11}{2} ) + 24 = -\frac{25}{4}
  • vertex (-\frac{11}{2}, -\frac{25}{4}) is in Quadrant 3 and is below the x-axis

This COULD be the graph of the rain gauge.

The graph should contain the vertex, x-intercepts (-3, 0) and (-8, 0), and y-intercept (0, 24)

******************************************************************************************

2) y = -x² - 6x - 8

  • a = -1 so the parabola opens DOWN
  • x = \frac{-b}{2a} = \frac{-(-6)}{2(-1)}  = \frac{6}{-2} = -3
  • y = -(-3)² - 6(-3) - 8 = -9 + 18 - 8 = 1
  • vertex (-3, 1) is in Quadrant 2 and is above the x-axis

This could NOT be the graph of the rain gauge.

The graph should contain the vertex, x-intercepts (-2, 0) and (-4, 0), and y-intercept (0, -8)

******************************************************************************************

3) y = x² - 2x + 3

  • a = 1 so the parabola opens UP
  • x = \frac{-b}{2a} = \frac{-(-2)}{2(1)}  = \frac{2}{2} = 1
  • y = (1)² - 2(1) + 3 = 1 - 2 + 3 = 2
  • vertex (1, 2) is in Quadrant 1 and is above the x-axis

This could NOT be the graph of the rain gauge.

The graph should contain the vertex, y-intercept (0, 3), and its mirror image (2, 3). <em>There are no x-intercepts</em>

******************************************************************************************

4) y = x² + 4x + 4

  • a = 1 so the parabola opens UP
  • x = \frac{-b}{2a} = \frac{-4}{2(1)}  = -2
  • y = (-2)² + 4(-2) + 4 = 4 - 8 + 4 = 0
  • vertex (-2, 0) is in Quadrant 2 and is on the x-axis

This COULD be the graph of the rain gauge.

The graph should contain the vertex, y-intercept (0, 4), and its mirror image (-4, 4). <em>The x-intercept is the vertex.</em>

Compared to the other four graphs, this is most likely the equation for the rain gauge!

******************************************************************************************

5) y = 3x² + 21x + 30

  • a = +3 so the parabola opens UP
  • x = \frac{-b}{2a} = \frac{-21}{2(3)}  = -\frac{7}{2}
  • y = 3(-\frac{7}{2})^{2} + 21(-\frac{7}{2} ) + 30 = -\frac{27}{4}
  • vertex (-\frac{7}{2}, -\frac{27}{4}) is in Quadrant 3 and is below the x-axis

This COULD be the graph of the rain gauge.

The graph should contain the vertex, x-intercepts (-2, 0) and (-5, 0), and y-intercept (0, 30)

*******************************************************************************************

4 0
3 years ago
Read 2 more answers
Graph the equation and identify the​ y-intercept.
Hunter-Best [27]

We need the graphing tool.

4 0
3 years ago
Rounded to the nearest hundredth, what is the positive solution to the quadratic equation 0 = 2x2 + 3x – 8? Quadratic formula: x
OleMash [197]

ANSWER



x=1.39 to the nearest hundredth.



EXPLANATION



We have the equation,



0=2x^2+3x-8



Which can be rewritten as



2x^2+3x-8=0

The question demands the use of the quadratic formula.

Comparing this to the general quadratic equation;

ax^2+bx+c=0


a=2,b=3,c=-8


The quadratic formula is given by;


x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}


We now substitute all the values in to the formula;


x=\frac{-3\pm\sqrt{(3)^2-4(2)(-8)}}{2(2)}

We simplify to obtain;

x=\frac{-3\pm\sqrt{9+64}}{4}


x=\frac{-3\pm\sqrt{73}}{4}


We now split the plus or minus sign to obtain;


x=\frac{-3-\sqrt{73}}{4}


This implies that;


x=-2.89

Or

x=\frac{-3+\sqrt{73}}{4}


This will evaluate to;


x=1.39

Hence, the positive solution rounded to the nearest hundredth is

x \approx 1.39

6 0
4 years ago
Read 3 more answers
PLEASE HELP!!!
riadik2000 [5.3K]
The answer is a if the line is dotted/dashed. The answer is c if the line isn't dotted/dashed.
7 0
3 years ago
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The base of a statue of liberty is 154 feet tall.Is this number closer to 100 or 200?explain
mixer [17]
It is close to 200 because 150 or above would be rounded to 200. Below 150 would be 100
8 0
3 years ago
Read 2 more answers
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