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eduard
3 years ago
7

A balloon is filled with helium at sea level. The volume was measured to be 3.1 liters at a pressure of 0.97 atmosphere. If the

balloon is released, it drifts upward. At a height of 4 kilometers, the pressure is measured to be 0.61 atmospheres. What is the volume of the balloon?
Chemistry
2 answers:
Illusion [34]3 years ago
6 0
P1V1=P2V2 Boyle's law
0.97atm × 3.1L= 0.61atm × V2
V2= 4.9L
Vladimir79 [104]3 years ago
5 0

Answer:

The volume of the balloon is 4.92 L at the height of 4 km.

Explanation:

Initial Volume of the helium gas V_1= 3.1 L

Initial pressure of the helium gas P_1= 0.97 atm

Final volume of the helium gas = V_2

Final pressure of the helium gas =P_2=0.61 atm

Applying Boyle's law:

P_1V_1=P_2V_2 (At constant temperature)

V_2=\frac{P_1\times V_1}{P_2}=\frac{0.97 atm\times 3.1 L}{0.61 L}

V_2=4.92 L

The volume of the balloon is 4.92 L at the height of 4 km.

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GuDViN [60]

Answer:

0.00701 moles of neon gas will occupy 170 ml of volume under the same conditions.

Explanation:

The relationship of number of moles and volume at constant temperature and pressure was given by Avogadro's law. This law states that volume is directly proportional to number of moles at constant temperature and pressure.

The equation used to calculate number of moles is given by:

\frac{V_1}{n_1}=\frac{V_2}{n_2}

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V_1\text{ and }n_1 are the initial volume and number of moles

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We are given:

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Putting values in above equation, we get:

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V_2=\frac{211 mL\tomes 0.00701 mol}{0.00872 mol}=169.62 mL\approx 170 mL

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3 years ago
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