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eduard
3 years ago
7

A balloon is filled with helium at sea level. The volume was measured to be 3.1 liters at a pressure of 0.97 atmosphere. If the

balloon is released, it drifts upward. At a height of 4 kilometers, the pressure is measured to be 0.61 atmospheres. What is the volume of the balloon?
Chemistry
2 answers:
Illusion [34]3 years ago
6 0
P1V1=P2V2 Boyle's law
0.97atm × 3.1L= 0.61atm × V2
V2= 4.9L
Vladimir79 [104]3 years ago
5 0

Answer:

The volume of the balloon is 4.92 L at the height of 4 km.

Explanation:

Initial Volume of the helium gas V_1= 3.1 L

Initial pressure of the helium gas P_1= 0.97 atm

Final volume of the helium gas = V_2

Final pressure of the helium gas =P_2=0.61 atm

Applying Boyle's law:

P_1V_1=P_2V_2 (At constant temperature)

V_2=\frac{P_1\times V_1}{P_2}=\frac{0.97 atm\times 3.1 L}{0.61 L}

V_2=4.92 L

The volume of the balloon is 4.92 L at the height of 4 km.

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Answer:

C₃H₈(g) + 6 H₂O(g) ⇒ + 10 H₂(g) + 3 CO₂(g)

Explanation:

Propane can be turned into hydrogen by the two-step reforming process.

In the first step, propane and water react to form carbon monoxide and hydrogen. The balanced chemical equation is:

C₃H₈(g) + 3 H₂O(g) ⇒ 3 CO(g) + 7 H₂(g)

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C₃H₈(g) + 3 H₂O(g) + 3 CO(g) + 3 H₂O(g) ⇒ 3 CO(g) + 7 H₂(g) + 3 H₂(g) + 3 CO₂(g)

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