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3 years ago

What is the mass of and object with a volume of 100 cm3 and a density of 10 g/cm3?

Chemistry

1 answer:

nadezda [96]3 years ago

4 0

Answer:

1000 g

Explanation:

d = m/v

We are given d: 10g/cm3

and v: 100cm3

Plug them into the equation to get 10 = m/100

Then, cross multiply 10x100 to get mass which is: 1000g

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If kc = 0.143 at 25°c for this reaction, predict the direction in which the system will shift if the initial concentrations of c

GenaCL600 [577]

The equation is as follows:
Cyclohexane (C6H12) ⇔ Methyl cyclopentane (C6H12)
The equilibrium constant Kc = 0.143 >>> (1)
Qc is the reaction quotient
where; If Q = K >>>> No shift left or right >>> (2)
Q > K >>>> Reaction shifts left >>> (3)
Q < K >>>> Reaction shifts right >>> (4)
And in our equation; Q = 0.3 / 0.4 = 0.75 >>> (5)
From (1), (3) and (5), Q > Kc
∴ the reaction shifts left

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3 years ago

4. The cloud of interstellar dust and gas that forms a star is known as

Ede4ka [16]

It's called a nebula or nebulae (plural). They are not only massive clouds of dust, hydrogen and helium gas, and plasma; they are also often “stellar nurseries” – i.e. the place where stars are born.

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3 years ago

Can someone explain compressibility please ?

RUDIKE [14]

Compressibility refers to the amount or extent to which a substance can be compressed, also involving the the relationship between changes in volume due to applied pressure.

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3 years ago

5) How many Kilograms are in 12 L of Chlorine Gas?

melamori03 [73]

Answer: 0.03798 kilograms

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given volume}}{\text {Molar Volume}}=\frac{12L}{22.4L}=0.535moles$

1 mole of chlorine gas $(Cl_2)$ weighs = 71 g

Thus 0.535 moles of chlorine gas $(Cl_2)$ will weigh = $\frac{71}{1}\times 0.535=37.98g=0.03798kg$ (1kg=1000g)

Thus there are 0.03798 kilograms in 12 L of chlorine gas.

3 0

3 years ago

PLS help

viktelen [127]

Answer:

d . Sc2O5

Explanation:

Hello,

In this case, when forming oxides from a metal and oxygen, for us to find out each element's subscript, we must exchange them as shown below, considering +5 for scandium:

$Sc^{+5}_2O^{-2}_5$

For that reason, the answer is d . Sc2O5

Best regards.

3 0

3 years ago

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