How are biotic factors different from abiotic factors?
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Following reaction occurs in the given electrochemical system:
→ Fe + 
Thus, under standard conditions
E(0) = E(0) Fe2+/Fe - E(0) Zn2+/Zn
where,
= standard reduction potential of Fe2+/Fe = -0.44 v
= standard reduction potential of Zn2+/Zn = -0.763 v
E(0) = 0.323 v
now, we know that, ΔG(0) =-nFE(0) ............... (1)
Also, Δ
On equating and rearranging equation 1 and 2, we get
K = exp(
)= exp (
) = 8.46 x 
Thus, under standard conditions
E(0) = E(0) Fe2+/Fe - E(0) Zn2+/Zn
where,
E(0) = 0.323 v
now, we know that, ΔG(0) =-nFE(0) ............... (1)
Also, Δ
On equating and rearranging equation 1 and 2, we get
K = exp(