1) Percent composition
<span>Na: 13.60%,
N: 8.29%
C: 35.51%
H: 4.77%
O: 37.85%
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100.02%
2) Convert mass percent to molar composition
For that, divide the percent of each element by its atomic mass.
</span>
<span>Na: 13.60 / 22.99 = 0.5916
N: 8.29 / 14.01 = 0.5917
C: 35.51 / 12.01 = 2.9567
H: 4.77 / 1.01 = 4.7228
O: 37.85 / 16.00 = 2.3656
3) Divide each number by the smallest one:
</span>
<span><span>Na: 0.5916 / 0.5916 = 1.0
N: 0.5917 / 0.5916 = 1.0
C: 2.9567 / 0.5916 = 5.0
H: 4.7228 / 0.5916 = 8.0
O: 2.3656</span> / 0.5916 = 4.0
4) State the empirical formula: Na N C5 H8 O4
5) Calculate the mass of the empirical formula:
Multiplicate the number of each atoms times the atomic mass corresponding atomic mass of the atom.
1 * 22.99 + 1 * 14.01 + 5 * 12.01 + 8 * 1.01 + 4 * 16.00 = 169.13
6) Divide the molar mass by the mass of the empirical formula:
169 / 169.13 = 1
7) Conclusion: the molecular formula is Na N C5 H8 O4, so the number of atoms present in the compound formula are:
Na: 1
N: 1
C: 5
N: 8
O: 4
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Well, if the coefficients are both 1, then you will make 8.21 moles.
See the equation is:
x moles= (8.21mol FeS₂)×(1 mole H₂SO₄ ÷ 1 mole FeS₂) = 8.21 moles H₂SO₄
So if you change the coefficients of the equation, your product will be a different number.
Example:
x moles= (8.21mol FeS₂)×(2 mole H₂SO₄ ÷ 1 mole FeS₂) = 16.4 moles H₂SO₄
I hope this helps you out!
Brady
Answer:
organic molecules made up of carbon and hydrogen elements joined together in long groups called hydrocarbons. The arrangement of these hydrocarbon chains, and their interaction with each other, determines fat type.
The stoichiometry of the reaction gives the molar ratio in which the reactants react with each other and the ratio in which products are formed.
The coefficients of the reactants in the reaction follow the stoichiometry
the balanced chemical equation for the reaction is as follows;
2C₃H₆(g) + 9O₂(g) ---> 6CO₂(g) + 6H₂O(l)