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3 years ago

What is grassland animal

Physics

2 answers:

Phoenix [80]3 years ago

7 0

Answer:

Any animals that is home to a savannah or grassland, like a gopher, or a gazelle.

Explanation:

Hope this helps :)

vaieri [72.5K]3 years ago

6 0

Carnivores like lions, wolves, cheetahs and leopards are also found in temperate grasslands. Other animals of this region include deer, prairie dogs, mice, jack rabbits, skunks, coyotes, snakes, foxes, owls, badgers, blackbirds, grasshoppers, meadowlarks, sparrows, quails, hawks and hyenas.

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To solve this problem we will apply the concepts related to the conservation of kinetic energy and elastic potential energy. Thus we will have that the kinetic energy is

$KE = \frac{1}{2} mv^2$

And the potential energy is

$PE = \frac{1}{2} kx^2$

Here,

m = mass

v = Velocity

x = Displacement

k = Spring constant

There is equilibrium, then,

KE = PE

$\frac{1}{2} mv^2 = \frac{1}{2} kx^2$

Our values are given as,

$x=0.56m\\k=230N/m\\m=15kg$

Replacing we have that

$\frac{1}{2} (15)v^2 = \frac{1}{2} (230)(0.56)^2$

$v = 2.19m/s$

Therefore the speed of the cart is 2.19m/s

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A 1500 kg weather rocket accelerates upward at 10.0 m/s . It explodes 2.00 s after liftoff and breaks into two fragments, one tw

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20 m/s is the speed of the heavier fragment just after the explosion.

Newton's second law of motion states that the resultant force applied to an object is directly proportional to the mass and acceleration of the object.

F = ma where, F = Force (Newton)

m= mass

a = acceleration

Given:

mass of rocket = M = 1500 kg

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mass of heavier fragment = m₂ = 2m = 1000 kg

maximum height of lighter fragment = h = 530 m

Let's calculate the final speed of the rocket just before the explosion:

v = u + at