So you want to solve for x?
It would be nice if this would easily factor:
(-4x + 5)(2x +1) = 0 This will not work!
So you need to use the quadratic formula:
a = -8, b = 4, c = 5
x = (-4 +/-
)/2(-8)
= (-4 +/-
)/-16
= (-4 +
)/-16
= 1/4 -
/4
For short you call this scientific notation.
FIRST
Count how many time you need to move the decimal over to make your single digit more then 1 and less then 10. So we will erase the 0's as we go along.
167000,000,000,000
So in this case we want to make the single digit 1.67 so it can be greater then 1 and less then 10
So now we see how many times we need to move the decimal and when you cant see the decimal just imagine it at the very end of the problem
167000,000,000,000
(For the mods out there I copied and pasted the bold number so i didn't have to take a while to retype the whole number. Thanks.)
SO NOW I get 14 because that's how many spots the decimal moved over.
Now since we need to right it in SN we need to write out this
X*10^X
The exponent X stands for how many times we moved the decimal over. I got 14 so we have that exponent
X*10^14
NOW We need to fiqure out X.... X was just the number we made greater then one and less then 0.
So thats 1.67
So we get
1.67*10^14
Did this help? <3
Answer:
B) ![\sqrt[4]{80} ^x](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B80%7D%20%5Ex)
Step-by-step explanation:
The given expression is 
It is 4th root. because 1/4 represents the 4th root.
So,
Therefore, the answer is B)
11
A diagonal connects a vertex to another vertex without being a side of the polygon. There are 14 vertices in a 14-gon. This leaves 13 vertices left to connect to (since we cannot connect the vertex to itself). However, two of these vertices will form the sides of the 14-gon. This leaves us with 11 possible diagonals we can draw.
