How much soil is in a 5 cm to 9 cm deep hole?

A ball is thrown off a cliff at a speed of 10 m/s in a horizontally direction. The ball reaches the ground 1.5 seconds. If the b

Tems11 [23]

I am pretty sure it is d

5 0

2 years ago

Explain why steel is mor dense than water

natta225 [31]

Steel is more dense because it’s heavy while water is light

7 0

3 years ago

Read 2 more answers

You are standing on a large sheet of frictionless ice and holding a large rock. In order to get off the ice, you throw the rock

kondor19780726 [428]

Answer:

0.4778 m/s

Explanation:

To solve this question, we will make use of law of conservation of momentum.

We are given that the rock's velocity is 12 m/s at 35°. Thus, the horizontal component of this velocity is;

V_x = (12 m/s)(cos(35°)) = 9.83 m/s.

Thus, the horizontal component of the rock's momentum is;

(3.5 kg)(9.83 m/s) = 34.405 kg·m/s.

Since the person is not pushed up off the ice or down into it, his momentum will have no vertical component and so his momentum will have the same magnitude as the horizontal component of the rock's momentum.

Thus, to get the person's speed, we know that; momentum = mass x velocity

Mass of person = 72 kg and we have momentum as 34.405 kg·m/s

Thus;

34.405 = 72 x velocity

Velocity = 34.405/72

Velocity = 0.4778 m/s

6 0

3 years ago

What kind of circuit is the one shown below?

lions [1.4K]

Answer:

The given circuit diagram shows parallel circuit.

Explanation:

In this circuit diagram two bulbs are connected in parallel combination because current flows from the battery gets bifurcated at the junction. Thus, two bulbs are connected in parallel combination.

This parallel combinations of bulbs then connected to the battery given in the diagram. So, the combinations of bulbs are connected in parallel combinations with the battery.

Hence, both bulbs and battery are connected in parallel combinations with each other.

The circuit diagram shown in figure is parallel.

8 0

3 years ago

Read 2 more answers

An insulating cup contains 200 grams of water at 25 ∘C. Some ice cubes at 0 ∘C is placed in the water. The system comes to equil

Nataly [62]

Answer:

The amount of ice added in gram is 32.77g

Explanation:

This problem bothers on the heat capacity of materials

Given data

Mass of water Mw= 200g

Temperature of water θw= 25°c

Temperature of ice θice= 0°c

Equilibrium Temperature θe= 12°c

Mass of ice Mi=???

The specific heat of ice Ci= 2090 J/(kg ∘C)

specific heat of water Cw = 4186 J/(kg ∘C)

latent heat of the ice to water transition Li= 3.33 x10^5 J/kg

heat heat loss by water = heat gained by ice

N/B let us understand something, heat gained by ice is in two phases

Heat require to melt ice at 0°C to water at 0°C

And the heat required to take water from 0°C to equilibrium temperature

Hence

MwCwΔθ=MiLi +MiCiΔθ

Substituting our data we have

200*4186*(25-12)=Mi*3.3x10^5+

Mi*2090(12-0)

837200*13=Mi*3.3x10^5+Mi*2090

10883600=332090Mi

Mi=10883600/332090

Mi= 32.77g

4 0

3 years ago