-- We're pretty sure that this question is based on an assumption of EARTH, so we know that we're dealing with a sphere of roughly 3.950 miles radius.
-- The distance on the sphere between 30° west and 60° east is 90° of longitude. That's 1/4 of the total circumference of the circle.
-- BUT ..... Way up here at 60° N latitude, the circle is not as big as the equator. It's radius/diameter/circumference is only cos(60°) = 0.5 of the Earth's total.
-- So the length of our quarter-circle arc is about
(1/4) x (2 · π · 3,950 miles) x (0.5) =
(1/4) x (3,950 π miles) =
988 π miles = 3,104 miles
Answer:
v_{ average} = 5.57
Explanation:
The most probable value of a measure is
v_average = 
∑ x_i
where N is the number of measurements
in tes case N = 3
v_{average} = ⅓ (5.63 +5.54 + 5.53)
V_{average} = 5,567
The number of significant figures must be equal to the number of figures that have the least in the readings.
v_{ average} = 5.57
F has direct relation with a
then doubling F cause acc. to get double i:e 6×2=12
The spring constant is 147 N/m
Given the mass of the block is 2.00 kg , the mass of the body is 300 g and the length of the spring is 2.00 cm
We need to find the spring constant
A spring is an object that can be deformed by a force and then return to its original shape after the force is removed.
The force required to stretch an elastic object such as a metal spring is directly proportional to the extension of the spring
We know that F = kx
300(9.8)= k (0.02)
k = 147.15 N/m
Rounding off to the nearest is 147N/m
The spring constant is 147N/m
Learn more about Hooke's law here
brainly.com/question/15365772
#SPJ4
