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vitfil [10]
3 years ago
6

Multi celled organisms have a ______ surface area to volume ratio than single celled organisms.

Physics
1 answer:
True [87]3 years ago
6 0
A. Larger. It is larger Bc they r all larger than the other
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What is the difference between: first moment of area and second moment of area?
zhannawk [14.2K]
To determine the centroid of the object first moment of area is used.

To predict the resistance of a shape to bending and deflection which are directly proportional, second moment of area is used.

6 0
3 years ago
A train has a length of 81.1 m and starts from rest with a constant acceleration at time t = 0 s. At this instant, a car just re
arlik [135]

Answer: a) vcar= 7 m/s ; b) a train= 0.65 m/s^2

Explanation: By using the kinematic equation for the car and the train we can determine the above values of the car velocity and the acceletarion of the train, respectively.

We have for the car

distance = v car* t, considering the length of train (81.1 m) travel by the car during the first 11.6 s

the v car =  distance/time= 81.1 m/11.6s= 7 m/s

In order to calculate the acceleration we have to use the kinematic equation for the train from the rest

distance train = (a* t^2)/2

distance train : distance travel by the car at constant speed

so distance train= (vcar*36.35)m=421 m

the a traiin= (2* 421 m)/(36s)^2=0.65 m/s^2

4 0
3 years ago
HELP ASAP!!
andriy [413]

Answer:

This is false becuase different object weigh different

Thank you!

Explanation:

3 0
3 years ago
What's is the kinetic energy of a .235-kg baseball thrown at 50.0m/s
san4es73 [151]

Answer:

34.51

Explanation:

k=1/2mv² is the kenetic energy equation to fill is in

k=[1/2(0.235)×50]²

6 0
2 years ago
Water flows from a large drainage pipe at a rate of 950 gal/min. What is this volume rate of flow in (a) m3/s , (b) liters/min,
Paladinen [302]

Answer:

0.05997\ m^3/s

3596.1395\ L/min

2.11647\ ft^3/s

Explanation:

1\ gal/min=\dfrac{1}{264\times 60}\\\Rightarrow 950\ gal/min=950\times \dfrac{1}{264\times 60}\\\Rightarrow 950\ gal/min=0.05997\ m^3/s

Volume rate of flow is 0.05997\ m^3/s

1\ gal/min=3.78541\ L/min\\\Rightarrow 950\ gal/min=950\times 3.78541=3596.1395\ L/min

Volume rate of flow is 3596.1395\ L/min

1\ gal/min=\dfrac{1}{7.481\times 60}\\\Rightarrow 950\ gal/min=950\times \dfrac{1}{7.481\times 60}\\\Rightarrow 950\ gal/min=2.11647\ ft^3/s

Volume rate of flow is 2.11647\ ft^3/s

6 0
3 years ago
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